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3 years ago

Prisha rolls a fair number cube multiple times and records the result of each roll. Her results are shown in the table.

Mathematics

2 answers:

Leona [35]3 years ago

7 0

Answer:

The experimental probability of rolling a 3 is greater than the theoretical probability of rolling a 3

Step-by-step explanation:

* Lets explain the difference between the theoretical probability and

experimental probability

- Theoretical probability is what we expect to happen

- Experimental probability is what actually happens when we try it out

- Both of them calculated by the same way, the number of possible ways

an outcome can occur divided by the total

* Lets solve the problem

- The table has two column;

# Number Cube # Observed Frequency

1 18

2 16

3 24

4 26

5 16

6 20

Total 120

∵ The experimental probability of rolling a 3 = 24/120 = 1/5 = 0.2

∴ The experimental probability of rolling a 3 = 0.2 = 20%

∵ The theoretical probability of rolling a 3 = 1/6

∴ The theoretical probability of rolling a 3 = 0.1666 ≅ 17%

∵ 20% is greater than 17%

∴ The experimental probability of rolling a 3 is greater than the

theoretical probability of rolling a 3

zepelin [54]3 years ago

6 0

Answer:

A - 1/30

Step-by-step explanation:

I just did it on edge-2020

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−−→ LO bisects ∠ NLM , LM = 18 , NO = 4 , and LN = 10 . LO → bisects ∠ NLM , LM = 18 , NO = 4 , and LN = 10 . What is the value

Sindrei [870]

Answer:

7.2

Step-by-step explanation:

Given that in triangle LMN, LO is angle bisector of angle L.

LN =10 and LM =18

By angle bisector theorem for triangles we have

LN/LM = NO/MO

Substitute the values for known things and x for MO

We get

10/18 = 4/x

Or cross multiply to get

10x=72

x=7.2

So answer is 7.2

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3 years ago

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Stels [109]

Answer:

13. c,

14. a.

Step-by-step explanation:

13. The length of a side PQ with coordinates of

P as (x,y) and Q as (w,z)

is: $\sqrt{(x-w)^{2} +(y-z)^{2} }$

so, the length of the side AB =

$\sqrt{(5-5)^{2}+(-2+7)^{2} } =\sqrt{0^{2}+5^{2} } =5$

the length of side BC =

$\sqrt{(5-1)^{2}+(-7+2)^{2} } =\sqrt{(4)^{2}+(-5)^{2} } =\sqrt{4^{2}+5^{2} }$

the length of side AC=

$\sqrt{(5-1)^{2} +(-2+2)^{2} } =\sqrt{4^{2} } =4$

now, the easiest one will be when the vertices are on the coordinate axes.

so, option c will be the most appropriate one.

14. If u see the figure clearly, the lines l and FH are parallel.

the parallel postulate, i.e, the alternate interior angles will always be congruent.

here, the alternate interior angles are angle1 and angle4.

therefore to prove this step, he used parallel postulate as a reason.

so, the correct option is "a"

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d1i1m1o1n [39]

y = 6x - 4

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y = 6(1) - 4

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y = 18 - 4

y = 14

3 = 14

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y = 6(10) - 4

y = 60 - 4

y = 56

10 = 56

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