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Maksim231197 [3]
2 years ago
11

Prisha rolls a fair number cube multiple times and records the result of each roll. Her results are shown in the table.

Mathematics
2 answers:
Leona [35]2 years ago
7 0

Answer:

The experimental probability of rolling a 3 is greater than the theoretical probability of rolling a 3

Step-by-step explanation:

* Lets explain the difference between the theoretical probability and

 experimental probability

- Theoretical probability is what we expect to happen

- Experimental probability is what actually happens when we try it out

- Both of them calculated by the same way, the number of possible ways

 an outcome can occur divided by the total

* Lets solve the problem

- The table has two column;

# Number Cube             # Observed Frequency

           1                                           18

           2                                          16

           3                                          24

           4                                          26

           5                                          16

           6                                          20

        Total                                      120

∵ The experimental probability of rolling a 3 = 24/120 = 1/5 = 0.2

∴ The experimental probability of rolling a 3 = 0.2 = 20%

∵ The theoretical probability of rolling a 3 = 1/6

∴ The theoretical probability of rolling a 3 = 0.1666 ≅ 17%

∵ 20% is greater than 17%

∴ The experimental probability of rolling a 3 is greater than the

  theoretical probability of rolling a 3

zepelin [54]2 years ago
6 0

Answer:

A - 1/30

Step-by-step explanation:

I just did it on edge-2020

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a coin lands on heads 200 times. the relative frequency of heads is 0.4. how many times was the coin thrown?
Kazeer [188]

Answer:

The number of times coin thrown was <u>500</u>.

Step-by-step explanation:

Given:

A coin lands on heads 200 times. the relative frequency of heads is 0.4.

Now, to find the times coin was thrown.

Let the number of times coin thrown was be x.

Relative frequency = 0.4.

Number of lands on heads = 200.

So, to get the number of times coin was thrown we put formula:

Relative\ frequency=\frac{Number\ of\ lands\ on\ heads}{Number\ of\ times\ coin\ thrown}

0.4=\frac{200}{x}

<em>By cross multiplying we get:</em>

0.4x=200

<em>Dividing both sides by 0.4 we get:</em>

x=500.

Therefore, the number of times coin thrown was 500.

7 0
3 years ago
Read 2 more answers
The sum of the measures of angle LMN and angle NMP is 180 degrees
Vaselesa [24]

Answer:

angle LMN is 153 degrees.

Step-by-step explanation:

180 = 15g + 18 +3g; combine like terms

180 = 18g + 18; subtract 18 on both sides

162 = 18g; divide 18 on both sides

g = 9

plug in: 15(9) + 18 = 153

please mark brainliest if I helped you!

6 0
2 years ago
WILL GIVE BRAINLIEST!!!
grin007 [14]

Answer:

i think the second one

Step-by-step explanation:

i think it would be the smartest thing to pick

7 0
3 years ago
Help ur boy out abcdefghijklmnopqrstuvwxyz
Umnica [9.8K]

Answer:

  1. (-6, 10)
  2. (-10, 9)
  3. (-11, -6)
  4. (-5, 1)

Step-by-step explanation:

<em>(x,y) → (x-8, y+4)</em>

1. (2, 6)

(2-8, 6+4)

<u>(-</u><u>6, 10)</u>

2. (-2, 5)

(-2-8, 5+4)

<u>(-10, 9)</u>

3. (-3, -10)

(-3-8, -10+4)

<u>(-11, -6)</u>

ídk man u should connect it to <u>(11, -7)</u> since it's the only choice closest to the right answer, but If u can write the correct then write this. there's prolly an error in that quiz ídk

4. (3, -3)

(3-8, -3+4)

<u>(-5, 1)</u>

<u> </u>still not in the choices nanii but <u>(5, -14)</u> is the only choice left and also the closest, and even if u use calculator the correct answer is still (-5, 1). sigh, I hope this helper at least

5 0
3 years ago
Question 2 of 5
AlekseyPX

Given:

The different recursive formulae.

To find:

The explicit formulae for the given recursive formulae.

Solution:

The recursive formula of an arithmetic sequence is f(n)=f(n-1)+d, f(1)=a,n\geq 2 and the explicit formula is f(n)=a+(n-1)d, where a is the first term and d is the common difference.

The recursive formula of a geometric sequence is f(n)=rf(n-1), f(1)=a,n\geq 2 and the explicit formula is f(n)=ar^{n-1}, where a is the first term and r is the common ratio.

The first recursive formula is:

f(1)=5

f(n)=f(n-1)+5 for n\geq 2.

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 5. So, the explicit formula for this recursive formula is:

f(n)=5+(n-1)(5)

f(n)=5+5(n-1)

Therefore, the correct option is A, i.e., f(n)=5+5(n-1).

The second recursive formula is:

f(1)=5

f(n)=3f(n-1) for n\geq 2.

It is the recursive formula of a geometric sequence with first term 5 and common ratio 3. So, the explicit formula for this recursive formula is:

f(n)=5(3)^{n-1}

Therefore, the correct option is F, i.e., f(n)=5(3)^{n-1}.

The third recursive formula is:

f(1)=5

f(n)=f(n-1)+3 for n\geq 2.

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 3. So, the explicit formula for this recursive formula is:

f(n)=5+(n-1)(3)

f(n)=5+3(n-1)

Therefore, the correct option is D, i.e., f(n)=5+3(n-1).

6 0
3 years ago
Read 2 more answers
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