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Alexeev081 [22]
2 years ago
13

ANY HELP IS APPRECIATED YALL! PLEASE HELP A GIRL OUT :D THANK YOU FOR TAKING YOUR TIME TO HELP ME:)

Mathematics
2 answers:
malfutka [58]2 years ago
7 0

Answer:

the answer is d 405 miles

nignag [31]2 years ago
3 0
D. 180/4=45. That’s the distance in an hour. Then multiply that by 8.
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1.What is the core characteristic that defines a zero-based budget?
lakkis [162]

Answer:

1. You account for every dollar you make to where your budget shows you have $0

2. She will have $125 leftover to budget out as she sees fit

3. If she does not account for it she may over spend or think she has extra money

4. I would put it in savings

5. No this is not what it means. This means that your paycheck will be able to cover your expenses.

6. You should put extra money in savings. You never know what will occur and savings can always help.

Step-by-step explanation:

7 0
3 years ago
What is the value of f(x) when x = 3?
Maksim231197 [3]
It's not specific enough to solve...so far it would only be f(3)
4 0
3 years ago
2 Points
vodomira [7]

1 is the magnitude of this question bro because it is process

3 0
3 years ago
Read 2 more answers
Nancy's garden has the dimensions shown 4 1/2 yard<br><br> 3 3/4 yd . She need find the area
Marina86 [1]

Answer:

The area of Nancy's garden is 16\frac{7}{8}\ yd^{2}

Step-by-step explanation:

I assume that the Nancy's garden is a rectangle shape

To find the area first convert mixed number to an improper fraction

4\frac{1}{2}\ yd=\frac{4*2+1}{2}=\frac{9}{2}\ yd

3\frac{3}{4}\ yd=\frac{3*4+3}{4}=\frac{15}{4}\ yd

Therefore

The area is equal to

A=\frac{9}{2}*\frac{15}{4}=\frac{135}{8}\ yd^{2}

convert to mixed number

\frac{135}{8}\ yd^{2=\frac{128}{8}+\frac{7}{8}=16\frac{7}{8}\ yd^{2}

4 0
3 years ago
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
2 years ago
Read 2 more answers
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