Question

20 pts look at pic n answer

Answer 1

1. $\frac{x^3}{x^8}=x^{-5}$

2. $\frac{6x}{2x^8} = 3x^{-7}$

3. $\frac{28x^6}{21x^2} = \frac{4}{3}x^4$

Step-by-step explanation:

1. x^3/x^8

Given fraction is:

$\frac{x^3}{x^8}$

When the bases are same in both numerator and denominator then the exponents can be added

i.e.

$\frac{x^a}{x^b} = x^{a-b}$

So,

$\frac{x^3}{x^8} = x^{3-8} = x^{-5}$

Part b:

$\frac{6x}{2x^8}\\= \frac{3.2.x}{2.x^8}\\=\frac{3x}{x^8}\\=3x{1-8}\\=3x^{-7}$

Part c:

Given

$\frac{28x^6}{21x^2}\\= \frac{7.4.x^6}{7.3.x^2}\\=\frac{4}{3} x^{6-2}\\=\frac{4}{3}x^4$

Keywords: Fractions, exponents

Learn more about fractions at:

• brainly.com/question/5282516
• brainly.com/question/5424148

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