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Angelina_Jolie [31]
3 years ago
14

A college surveys 300 graduates and finds 98 graduated with honors and 207 had one or both parents graduate from college. Of the

98 students with honors, 79 had one or both parents graduate from college. Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Mathematics
1 answer:
musickatia [10]3 years ago
4 0

Answer:

20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Graduated with honors:

98 students graduated with honors. Of those, 79 had at least one parent graduating from college. So 98 - 79 = 19 did not.

Of 300 students, 207 had one or both parents graduate from college. So 300 - 207 = 93 did not have at least one parent graduating.

Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

Of the 93 with no graduated parent, 19 earned honors

19/93 = 0.2043

20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

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adelina 88 [10]

Answer:

123 + (456 + 789)

Step-by-step explanation:

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3 years ago
When reading a book, Charlie made a list by writing down the page number of the last page he finished reading at the end of each
Assoli18 [71]

Answer:

No. of pages he read by the end of the 8th day = 425

Step-by-step explanation:

Charlie started from page 1 and read the same number of pages each day. Suppose x is the number of pages he read each day, the last page he read on the first day would be:

<u>Last page for day 1 = 1 + x</u>

This would be the first number he noted on the list.

The second page number can be determined by adding the number of pages he read to the last page for day 1.

Last page for day 2 = 1 + x + x

                                 = 1 + 2x

Similarly, the last page he read on the third day is:

Last page for day 3 = 1 + 3x. Similarly,

Last page for day 4 = 1 + 4x

Last page for day 5 = 1 + 5x

Last page for day 6 = 1 + 6x

Last page for day 7 = 1 + 7x

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His Mom added all of the page numbers and got a total of 432. So,

432 = 1+x + 1+2x + 1+3x + 1+4x + 1+5x + 1+6x + 1+7x + 1+8x

432 = 8 + 8x

8x = 432-8

8x = 424

x = 424/8

x = 53

By the end of the 8th day he actually read 1 + 8x pages. Substituting the value of x in this expression, we get:

No. of pages he read by the end of the 8th day = 1 + 8(53)

                                                                               = 1 + 424

No. of pages he read by the end of the 8th day = 425

4 0
4 years ago
Carlos is analyzing the results of an experiment on two groups of mice in which he compared the difference in their weight gain
Arlecino [84]
Given:difference in the mean weight gain is 0.60 gramsstandard deviation of the difference in sample mean is 0.305
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3 years ago
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