The ages of the students in a dance class are 10, 9, 11, 12, 9, 10, 9, 10, 11, 12, 8, 12, 12.
faust18 [17]
Answer:
Put the numbers in order then find the number that appears the most which is 12.
Step-by-step explanation:
Answer:
D an = 9 + 7(n-1)
Step-by-step explanation:
In the question, Max has 9 logs in the first load. But, after the seventh load he has a total of 51 logs. So the n would be your logs in the stack, which is 51. And since there is a total of 51 logs after the seventh load. It would be 9 plus 7 in parenthesis of 51 minus one, which is 50. So 50 times 7 comes down to 350 plus nine which comes down to a total of 359.
You would use the formula for the specific term you wish to find;
The formula is:

a = starting value of the sequence
d = the common difference (i.e. the difference between any two consecutive terms of the sequence)
n = the value corresponding to the position of the desired term in the sequence (i.e. 1 is the first term, 2 is the second, etc.)
Un = the actual vaue of the the term
For example, if we have the arithmetic sequence:
2, 6, 10, 14, ...
And let's say we want to find the 62nd term;
Then:
a = 2
d = 4
(i.e. 6 - 2 = 4, 10 - 6 = 4, 14 - 10 = 4;
You should always get the same number no matter which two terms you find the difference between so long as they are both
consecutive [next to each other], otherwise you are not dealing with an arithmetic sequence)
n = 62
And so: