3y = 5x + 30

y + 5x = 50 .......(1)

3y - 5x = 30 .....(2) - rearranging the first equation.

Add (1) and (2):-

4y = 80

y = 20
Now plug y = 20 into equation (1):-
20 + 5x = 50
5x = 30
x = 6

The 2 numbers are 6 and 20.

5 0

2 years ago

Read 2 more answers

Using the graphing calculator to locate the solutions of this system of equations

ivanzaharov [21]

Answer:

(±√3,±√+1)

Step-by-step explanation:

7 0

2 years ago

I need to know how to do these

Allisa [31]

I'll do one, you can use it as a basis for your answer.

$7x ^{2} + 6 = 13$

Subtract 6 from both sides to get X by itself.

$7x ^{2} = 7$

Now we divide by 7 for both sides as well.

$x {}^{2} = 1$

Now we find the square root of 1 to figure out X.

$\sqrt{1} = 1$

Therefore, X=1.

my first answer in about a month. hope this helped.

3 0

2 years ago