Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500
Waning gibbous
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Your answer is: <span>A) Lemon juice, water, Tums </span>
Answer:
The answer is the turns are formed from complementary base pairing and cause separation of the RNA transcript and RNA polymerase.
Explanation:
The turns are formed from complementary base pairing and cause separation of the RNA transcript and RNA polymerase.
The different combination of alleles for two genes must be due to "Crossing Over" [ Process occurs after fertilization, inter-changing of characters ]
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