Answer:
B) yes no yes
Explanation:
Particulars Product X Product Y Product Z
Units Produced 2,000 2,500 3,500
Sales value at split-off $15 $19 $20
Add: Processing cost $5 $7 $7
Sales after processing $24 $24 $29
Profit after
processing further $24- $15 - $5 $24 - $19 - $7 $29 - $20 - $7
= $4 = - $2 = $2
Yes No Yes
Since revenue after split off is from Product X and product Z, Product Y is creating negative profit that is loss from further processing.
Correct option
B) yes no yes
<u>Solution and Explanation:</u>
<u>
Answer:1</u> The total annual cash inflows associated with the new machine for capital budgeting purposes is:
![=\$ 5200+(2000 * \$ 2.40 \text { per dozen })](https://tex.z-dn.net/?f=%3D%5C%24%205200%2B%282000%20%2A%20%5C%24%202.40%20%5Ctext%20%7B%20per%20dozen%20%7D%29)
=$10000
<u>Answer:2 </u>The internal rate of return promised by the new machine to the nearest whole percent is:
Particulars Year Amount ($)
Cash outflow 0 -40000
Cash inflow 1 10000
2 10000
3 10000
4 10000
5 10000
6 10000
IRR 13%
=13% using IRR function in excel.
<u>Answer:3</u> IRR=17%
with salvage value
Particulars Year Amount ($)
Cash outflow 0 -40000
Cash inflow 1 10000
2 10000
3 10000
4 10000
5 10000
6 22000
IRR 17%
using IRR function in excel.
Answer:
Make sure that your work is properly marked
Explanation:
Answer:
10 to 15
Explanation:
Business messaging in accounting can be described as a set of channels that provide means by which the firms/ company and the consumer can have effective communication.
The primary business message is very essential in business, it must reflect clarity as well as simplicity, it enables company to pass their overarching information to the consumer, they are intentional content. In a situation whereby operations in a company needed relocation, primary message is passed. It should be noted that For an effective frame, the primary business message should be approximately 10 to 15 words in length.
Answer:
6k
Explanation:
Differentiate X3+ 3X2+X.The rules of differentiation say that if y= kX^n then dy/dx = knX^n-1. Therefore, X^3 would become 3X^2, 3X^2 would become 6X