Question

Can someone help fast please

Answer 1

Answer:

$\frac{3a}{a-2}$

Step-by-step explanation:

$\frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14}$

Factorise $2a^2 - 11a + 14}$

$\frac{2a - 7}{a}*\frac{3a^2}{(2a - 7)(a - 2)}$

$2a - 7$ cancels  2a - 7

$\frac{1}{a}*\frac{3a^2}{(1))(a - 2)}$

$\frac{1(3a^2)}{a(a-2)}$

$\frac{a(3a)}{a(a-2)}$

"a" cancels "a"

$\frac{3a}{a-2}$

Thus,

$\frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14}$ = $\frac{3a}{a-2}$