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mr_godi [17]
3 years ago
6

Can someone help fast please

Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

\frac{3a}{a-2}

Step-by-step explanation:

\frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14}

Factorise 2a^2 - 11a + 14}

\frac{2a - 7}{a}*\frac{3a^2}{(2a - 7)(a - 2)}

2a - 7 cancels  2a - 7

\frac{1}{a}*\frac{3a^2}{(1))(a - 2)}

\frac{1(3a^2)}{a(a-2)}

\frac{a(3a)}{a(a-2)}

"a" cancels "a"

\frac{3a}{a-2}

Thus,

\frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14} = \frac{3a}{a-2}

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