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IceJOKER [234]
3 years ago
5

How can you tell by looking at the coordinates of the two triangles that δ a'b'c' is a 180° rotation of δ abc?

Mathematics
1 answer:
irga5000 [103]3 years ago
5 0

Answer:

Option d is correct.

Both the x and y coordinates of the point on δa'b'c' have opposite signs from the corresponding points on δabc.

Step-by-step explanation:

The rule of 180 degree rotation about the origin is:

(x, y) \rightarrow (-x , -y)

Since a Rotation of a point through 180°, about the origin when a point a(h, k)  is rotated about the origin through 180° in anticlockwise or clockwise direction.

then, By the rule of 180 degree rotation;

a(h, k) \rightarrow a'(-h , -k)

so, it takes the new position i.e, a'(-h , -k)

Therefore, both the x and y coordinates of the point on δa'b'c' have opposite signs from the corresponding points on δabc.



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0.61m - 1.51m = 9 Solve for x
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The equation C = 5 9 F − 160 9 gives the relation between temperature readings in Celsius and Fahrenheit.
Pavel [41]

Step-by-step explanation:

The question is wrong. The correct equation is :

C=\frac{5}{9}F-\frac{160}{9}

We know that the equation gives the relation  between temperature readings in Celsius and Fahrenheit.

Therefore, giving that we know the value in Fahrenheit ''F'' we can find the reading in Celsius ''C''. This define a function C(F) that depends of the variable ''F''.

So for the incise (a) we answer Yes, C is a function of F.

For (b) we need to find the mathematical domain of this function. Giving that we haven't got any mathematical restriction, the mathematical domain of the function are all real numbers.

Dom (C) = ( - ∞ , + ∞)

For (c) we know that the water in liquid state and at normal atmospheric pressure exists between 0 and 100 Celsius.

Therefore the range will be

Rang (C) = (0,100)

Now, we need to find the domain for this range. We do this by equaliting and finding the value for the variable ''F'' :

For C = 0 :

0=\frac{5}{9}F-\frac{160}{9} ⇒ F=32

And for C = 100 :

100=\frac{5}{9}F-\frac{160}{9} ⇒ F=212

Therefore, the domain as relating temperatures of water in its liquid state is

Dom (C) = (32,212)

For (d) we only need to replace in the equation by F=71 and find the value of C ⇒

C=\frac{5}{9}F-\frac{160}{9} ⇒

C=(\frac{5}{9})(71)-\frac{160}{9}

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3 years ago
What is the range of possible values for x?
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<span>base AB = 52 and vertical angle 2x + 34° </span>

<span>For the sine law </span>
<span>(sin 2x)/22 = (sin ADB)/AB </span>
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<span>(sin ADC)/AB = (sin BDC)/BC </span>

<span>it follows </span>
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George had one sheet of paper. He cut it into 6" x 5", and 3" x 6". What were the dimensions and total area of his original shee
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Answer:l={8}'' ,b={6}'',l={6}'' ,b={8}''

and area is=48 inch square

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area of sheet=l\times b

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=30 inch square

area of sheet second={3}''\times {6}''

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