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3 years ago

15

Pick any number. If that number is even, divide it by 2. If it's odd, multiply it by 3 and add 1. Now repeat the process with yo

ur new number. If you keep going, you'll eventually end up at 1. Every time.

2 answers:

Eva8 [605]3 years ago

5 0

4/2=2+1=3x3=9+1=10/2=5+1=6/2=3+1=4/2

Firlakuza [10]3 years ago

5 0

That is pretty darn cool.

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A courtyard in the shape of a right triangle is set in the middle of three square office buildings, with one office building alo

oksian1 [2.3K]

Answer:

The area of Building C minus the area of Building B equals the area of Building A.

3 0

3 years ago

A trailer will be used to transport several 40-kilogram crates to a store. The greatest amount of weight that can be loaded onto

nikklg [1K]

Answer:

24

Step-by-step explanation:

The total capacity of the trailer is 1,050 kg.

An 82-kg crate is already loaded on the trailer.

We subtract 82 kg from 1,050 kg to find out the amount of weight still available.

1,050 kg - 82 kg = 968 kg

The trailer can still carry another 968 kg.

Each additional crate weighs 40 kg.

We divide 968 kg by 40 kg to calculate the number of crates that can still be loaded.

(968 kg)/(40 kg) = 24.2

Since we cannot place 0.2 of a crate, we round 24.2 down to 24.

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3 years ago

Write the phrase as an expression. 5 less than 8 An expression is

Gnoma [55]

Answer:

5<8

Step-by-step explanation:

3 0

3 years ago

Find the angle between u = (-2,-5) and v = (5,2)

OleMash [197]

The angle between u = (-2,-5) and v = (5,2) is 134 degrees approximately.

<u>Solution:</u>

Given, two vectors are u = (-2, -5) and v = (5, 2)

We have to find the angle between two vectors.

We know that,

$a. b=\|a\| .\|b\| \times \cos \theta$

where $\theta$ is angle between vectors a and b

$\text { Now vectors are }(-2 \vec{\imath}-5 \vec{\jmath}) \text { and }(5 \vec{\imath}+2 \vec{\jmath})$

$(-2 \vec{\imath}-5 \vec{\jmath}) \cdot(5 \vec{\imath}+2 \vec{\jmath})=\sqrt{(-2)^{2}+(-5)^{2}} \times \sqrt{5^{2}+2^{2}} \times \cos \theta$

$\text { since }\|a\|=\sqrt{x^{2}+y^{2}} \text { for } a=x \vec{\imath}+y \vec{\jmath}$

$\begin{array}{l}{-10-10=\sqrt{29} \times \sqrt{29} \times \cos \theta} \\\\ {-20=29 \times \cos \theta} \\\\ {\cos \theta=\frac{-20}{29}} \\\\ {\theta=\cos ^{-1} \frac{-20}{29}} \\\\ {\theta=133.60}\end{array}$

Hence, the angle between given two vectors is 134 degrees approximately.

3 0

3 years ago

20. GEOMETRY The measures of two sides of a triangle are given. If p isthe perimeter, and p=10x+5y, find the measure of the thir

algol [13]

The perimeter of any shape is a measure of the length of the peripheral of that shape.

For a triangle, it is an addition of the length of the 3 sides.

P = a + b + c where a, b, c are the lengths of the individual sides.

p = 10x + 5y = (3x + 4y) + (5x - y) + c

Collecting like terms on the RHS, we have

p = 10x + 5y = 8x + 3y + c

Subtracting 8x + 3y from both sides to give c leaves us with

10x + 5y - (8x + 3y) = c

c = 10x - 8x + 5y - 3y

c = 2x + 2y

7 0

9 months ago