Solve each system using elimination. Each system only has one solution. Write your solution in the form (x, y).

You want to find out whether caffeine mitigates the effect of alcohol on reaction time. To study this, you administer to your su

Ymorist [56]

Answer:

First Question

lower limit of 9 mph $j = 8.5 \ mph$

upper limit of 9 mph $q = 9.5 \ mph$

Second Question

lower limit of 120 pounds is $i = 119.9 \ pounds$

upper limit of 120 pounds is $l = 120.1 \ pounds$

Third Question

lower limit of 187 pounds is $a = 186.75 \ pounds$

upper limit of 187 pounds is $b = 187.25 \ pounds$

Step-by-step explanation:

From the question we are told that

The amount of beer administered is three 12-ounce beers

The amount of coffee administered is two cups of coffee

The speed limit is 60-mph

The smallest unit of scale is 1 mph

The first subject scores 9 mph

Generally given that the smallest unit of scale is 1 mph then the deviation of 9 mph will be by $\frac{1}{2} \ mph$

Hence the lower limit of 9 mph is

$j = 9 - 0.5$

$j = 8.5 \ mph$

And the upper limit of 9 mph is

$q = 9 + 0.5$

$q = 9.5 \ mph$

Generally given that the measuring weight on a scale that is accurate to the nearest 0.2 pound then 120 pounds will deviate by $\frac{1}{0.2} \ pounds$

Hence the lower limit of 120 pounds is

$i = 120 - 0.1$

$i = 119.9 \ pounds$

And the upper limit of 120 pounds is

$l = 120 + 0.1$

$l = 120.1 \ pounds$

Generally given that the measuring weight on a scale that is accurate to the nearest 0.5 pound then 187 pounds will deviate by $\frac{1}{0.5} \ pounds = 0.25 \ pounds$

Hence the lower limit of 120 pounds is

$a = 187 - 0.25$

$a = 186.75 \ pounds$

And the upper limit of 120 pounds is

$b = 187 + 0.25$

$b = 187.25 \ pounds$

5 0

3 years ago

How mathematics involved in merchandising??

anygoal [31]

Merchandising math is a multifaceted topic that involves many levels of the retail process, including assortment planning, vendor analysis, mark-up and pricing, and terms of sale.

I hope this helps :)

7 0

3 years ago

4 2/3 divided by 1/2

dimulka [17.4K]

Answer:

9.33333333333

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A study is performed in San Antonio to determine whether the average weekly grocery bill per five-person family in the town is s

bogdanovich [222]

Answer:

No, the sample evidence is not statistically significant (P-value = 0.125).

To reject the null hypothesis, the P-value has to be smaller than the significance level, so the significance level to reject the null hypothesis has to be 0.125 or higher.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average weekly grocery bill per five-person family in San Antonio is significantly different from the national average.

Then, the null and alternative hypothesis are:

$H_0: \mu=131\\\\H_a:\mu\neq 131$

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=133.474.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=11.193.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{11.193}{\sqrt{50}}=1.583$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{133.474-131}{1.583}=\dfrac{2.474}{1.583}=1.563$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

This test is a two-tailed test, with 49 degrees of freedom and t=1.563, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t>1.563)=0.125$

As the P-value (0.125) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the average weekly grocery bill per five-person family in San Antonio is significantly different from the national average.

8 0

3 years ago

A gardener planted 5 rows of vegetables. Each row has 3 pepper plants and s squash plants. The garden contains a total of 20 pla

Natalija [7]

(5x3)(5xs)=20
Hope that helps

3 0

3 years ago