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bekas [8.4K]
3 years ago
10

Please answer this correctly without making mistakes

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
4 0
In 12 years it grew 15 feet
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Identify the values of the variables. Give your answers in simplest radical form. HELP ASAP!!
kumpel [21]

Answer:

B

Step-by-step explanation:

Since the triangle is right use the sine/ tangent ratios to solve for x and y

note sin60° = \frac{\sqrt{3} }{2} and tan60° = \sqrt{3}

sin60° = \frac{opposite}{hypotenuse} = \frac{3\sqrt{6} }{y}

ysin60° = 3\sqrt{6}

y × \frac{\sqrt{3} }{2} = 3\sqrt{6}

multiply both sides by 2 and divide by \sqrt{3}

y v= 6\sqrt{\frac{6}{3} } = 6\sqrt{2}

tan60° = \frac{opposite}{adjacent} = \frac{3\sqrt{6} }{x}

xtan60° = 3\sqrt{6}

x × \sqrt{3} = 3\sqrt{6}

divide both sides by \sqrt{3}

x = 3\sqrt{\frac{6}{3} } = 3\sqrt{2}


8 0
3 years ago
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Pls give an answer to <br> 7 (-2x+4)=-4x
Leto [7]
2.8

-14x+28=-4x
10x=28
X=2.8


Mark brainliest please
7 0
3 years ago
Can someone help me with these geometry questions? I can’t seem to understand them. If u find the answers, can u explain it too?
rusak2 [61]

<em>Question 5</em>

Vertical angles are <u>congruent</u>. Therefore, 3y=\boxed{150}. The sum of two supplementary angles equals \boxed{180^{\circ}}.

Therefore, 6x+150=\boxed{180}

<em>Question 6</em>

\angle b-14=90-\angle b\\\\2\angle b=104\\\\\angle b=\boxed{52^{\circ}}

<em>Question 7</em>

<em />\angle d+32=180-\angle d\\\\2\angle d=146\\\\\angle d=\boxed{73^{\circ}}

<em>Question 8</em>

<em />7x-80=3x\\\\-80=-4x\\\\x=20\\\\\implies \boxed{m\angle 1=m\angle 3=60^{\circ}}

6 0
1 year ago
A=5/6(B+C) SOLVE FOR C
Shalnov [3]

A = 5/6(B + C)

multiply 6 on both sides

6A = 5(B + C)

divide 5 from both sides

6A/5 = B + C

subtract B from both sides

6A/5 - B = C

3 0
3 years ago
Eli and Dylan are brothers and decide to have a race from one end of the street to the other. Since Eli is older, he gives Dylan
ICE Princess25 [194]

Answer:

x=4

sorry if its wrong i did my best

6 0
2 years ago
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