Answer:
d. 130
Step-by-step explanation:
<h3>
Answer:</h3>
x = 1
<h3>
Step-by-step explanation:</h3>
<em>The only solution is an extraneous solution</em>, which is to say the equation has no solution.
The rational expression reduces to -1 (for x≠1), which makes the equation ...
1 = 1/x
The only solution to this is x=1, which is specifically disallowed.
___
If you subtract the right side, the equation becomes ...
((-x+1)(x) +2(x)(x -1) -(x -1))/(x -1) = 0
(-x^2 +x +2x^2 -2x -x +1)/(x -1) = 0 . . . . eliminate parentheses in the numerator
(x^2 -2x +1)/(x -1) = 0 . . . . . . . . . . . . . . . collect terms
(x -1)^2/(x -1) = 0 . . . . . . . . . . . . . . . . . . . factor
This is undefined for the only value of x that could possibly be a solution, x=1.
Step-by-step explanation:
Use the Pythagorean theorem:
We have
Substitute:
<em>subtract 16 from both sides</em>
Substitute:
Answer:
The food store used 3 lbs of clusters, 6 lbs of granola, and 3 lbs of raisins.
Step-by-step explanation:
Given that:
A food store makes a 12-lb mixture of granola, clusters, and raisins.
The cost of granola = 1.00 per pound
The cost of clusters = 3.00 per pound
The cost of raisins = 2.00 per pound
Let granola be = g; cluster be c and raisins be r
Then, g + c + r = 12
Similarly, the mixture calls for twice as much granola as clusters.
2c + c + r = 12
3c + r = 12
r = 12 - 3c
2c(1) + 3c + 2r = 21
2c + 3c + 2r = 21
5c + 2r = 21
5c + 2(12 -3c) = 21
5c + 24 - 6c = 21
24 - c = 21
-c = 21 - 24
c = 3
Thus, cluster c = 3 lbs
granola = 2(c) = 2(3) = 6 lbs
raisins = 12 - 3c
= 12 - 3(3)
= 12 - 9
raisins = 3 lbs
