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leonid [27]
3 years ago
6

Which equation is not equivalent to the other equations?

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0
I think the answer is C. X*4=-12+3
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A tank contains 250 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
VashaNatasha [74]

Answer:

A(t)=250-210e^{-\frac{t}{50}}

Step-by-step explanation:

We are given that

Volume,V=250 L

Mass of salt=m=40 g

Brine containing 1 g per liter

Pumped into the tank at the rate=5 L/min

We have to find the number A(t) of grams of salt in the tank at time t.

Rate of change of salt in the tank

\frac{dA}{dt}=Rate in-Rate out

Rate in=5 L/min

Rate out=\frac{A}{250}\times 5=\frac{A}{50} L/min

\frac{dA}{dt}=5-\frac{A}{50}=\frac{250-A}{50}

\int \frac{50dA}{250-A}=\int dt

-50ln(250-A)=t+C

Using the formula

\int \frac{dx}{x}=ln x

A=40 and t=0

-50ln(250-40)=0+C

-50ln(210)=C

Substitute the value

-50ln(250-A)=t-50ln(210)

-50ln(250-A)+50ln(210)=t

50ln\frac{210}{250-A}=t

t=50ln\frac{210}{250-A}

\frac{t}{50}=ln\frac{210}{250-A}

\frac{210}{250-A}=e^{\frac{t}{50}

\frac{250-A}{210}=e^{-\frac{t}{50}}

250-A=210e^{-\frac{t}{50}}

A(t)=250-210e^{-\frac{t}{50}}

8 0
4 years ago
I GIVE BRAINLIEST FOR EXPLANATION AND CORRECT ANSWER EXTRA POINTS 2
GaryK [48]

Answer:

See below, please!

Step-by-step explanation:

You can use the cos ratio to find the value of x. Since we know cosine is adjacent/hypotenuse, we can do cos(60)=x/40. Then, we multiply each side by 40 to find the value of x. So, x=20.

3 0
3 years ago
Simplify 8(5y-4x)/15 - ( - 3x + 7y/2 +3x - 4y)​
vekshin1

Answer:

that's it I think its clear

7 0
4 years ago
Solve this please!!!!!​
Vilka [71]
Answer: Do mind that I don’t completely trust that I am right, but I ask that you have faith in me.

So if I’m thinking correctly we subtract 180 from 217 which gives us 37. We then add that to 104 and subtract the sum from 180 which gives us b. So,

180-104+37
180-141=39

So b should equal 39 degrees, to check we add all the respective angles up,

104+39+37=180
4 0
3 years ago
Given square JKLM and t(-6,4) t (1,5) ​(JKLM)​RSTU, what is the area of​ RSTU?
Dafna1 [17]

Answer:

  • 144 cm²

Step-by-step explanation:

<u>The given translation doesn't change the shape or dimensions, hence the area remains same:</u>

  • A = a² = (12 cm)² = 144 cm²
5 0
2 years ago
Read 2 more answers
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