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vovikov84 [41]
3 years ago
15

List all number sets that apply to each number

Mathematics
1 answer:
kolbaska11 [484]3 years ago
5 0

Answer:

45

2

03

16

26

224

Step-by-step explanation:

You might be interested in
What is the volume of the square pyramid with the base edges 24 ft and height
liberstina [14]

Answer:

A

Step-by-step explanation:

The volume of a pyramid is one third the height times the area of the base.

V = ⅓ h A

The base is a square, so the area is the width times length.

V = ⅓ h wl

Problem is, we don't know the height, only the slant length.  But we can use this to find the height.

If we cut a cross section down the middle of the pyramid, we get an isosceles triangle.  The base of the triangle is 24, and the legs are 37.

If we cut this triangle in half, we get two right triangles.  Each right triangle has a base of 12 and a hypotenuse of 37.

Now we can use Pythagorean theorem to find the height of the triangle, which is also the height of the pyramid.

c² = a² + b²

37² = 12² + h²

h = 35

Now we can find the volume.  h = 35, w = 24, and l = 24:

V = ⅓ h wl

V = ⅓ (35) (24) (24)

V = 6720

So the volume is 6720 ft³, or answer A.

8 0
3 years ago
An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)

(b)Flight Direction of Y

Using Law of Sines

\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)

The direction of flight Y to the nearest degree is 39 degrees.

7 0
3 years ago
A bookshelf sits on top of a large desk. Together, their height is 6.75 feet. The difference between their heights is 1.85 feet.
slavikrds [6]

Answer: 4.9

Step-by-step explanation:

8 0
3 years ago
Si en una sustracción se disminuye el minuendo en 5 y se aumenta el sustraendo en 5 ¿que sucede con el resultado?
dimaraw [331]
Hi you look so pretty and gorgeous for me and do you want to be my friend.
3 0
3 years ago
Can someone help me please..
Elza [17]
So just find circumference is
circumfernce=2pir or pid
so diameter 2.5 ft
just for this problem aprox pi=3.14 so
c=pid
c=3.14(2.5)
c=7.85

a. 7.85 ft

b. how many times revolution till one mile (5280)
so
7.85 times x revolutions=5280
divide both sides b y7.85
x revolutions=672.61
round up so we complete the mile (about how many times..)
673 is the answer


a. 7.85 ft
b. 673 times
5 0
3 years ago
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