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Tems11 [23]
3 years ago
5

Ethan says it would require more than 100 moons to equal the mass of the Earth. Is this correct? Support your answer with your w

ork.
Please show work
Mathematics
1 answer:
vivado [14]3 years ago
3 0

Answer:

no

Step-by-step explanation:

because,THE MOON IS SMALLER ACROSS (IN DIAMETER) THAN THE UNITED STATES IS WIDE. If the Earth were hollow, about 50 moons would fit inside. a. THE MOON IS SMALLER THAN THE EARTH: FIFTY MOONS WOULD FILL THE EARTH.

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8(2n - 5) = 3(6n - 2)
joja [24]

Answer:

n=-17

Step-by-step explanation:

8(2n-5)=3(6n-2)

1) Distributive property

16x-40=18x-6

16x−40=18x−6

2) Subtract 16x16x from both sides.

-40=18x-6-16x

−40=18x−6−16x

3) Simplify 18x-6-16x18x−6−16x to 2x-62x−6.

-40=2x-6

−40=2x−6

4) Add 66 to both sides.

-40+6=2x

−40+6=2x

5) Simplify -40+6−40+6 to -34−34.

-34=2x

−34=2x

6) Divide both sides by 22.

-\frac{34}{2}=x

−

2

34

=x

7) Simplify \frac{34}{2}

2

34

to 17

−17=x

8) Switch sides.

x=−17

5 0
3 years ago
If y=3x+4 we’re changed to y=5x+4 how would the graph of the new function compare with the first one
xz_007 [3.2K]

Answer:

t would be steeper

Step-by-step explanation:

8 0
1 year ago
Solve for x.<br> a) 15<br> b) 38.5<br> c) 40<br> d) 25<br> e) 65
stiks02 [169]

Answer:

I have made it in above figure ans of this qn will option D

3 0
3 years ago
Order the following decimals from greatest to least (separated by
Feliz [49]

Answer:

0.14, 0.5, 0.71, 0.8, 0.83

7 0
2 years ago
Select the relations that are functions.
Arlecino [84]

Answer:

Depending on how the input of each function defined,

  • The first choice \left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace,
  • The third choice \left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace
  • The fourth choice \left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

  • be defined for all elements in the domain, and
  • map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element a from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be \lbrace a,\, 6, \, C\rbrace. Similarly, the domain for the third and fourth relations should be \lbrace 1,\, 2, \, 3\rbrace and \lbrace a,\, b, \, c\rbrace

8 0
3 years ago
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