A pole that is
1 answer:
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Answer:
Either: 1 neg, 3 pos, 0 imaginary; 1 neg, 1 pos, 2 imaginary
Step-by-step explanation:
Look for the positive possibilities first. Count the numbe of sign changes then subtract 2, if possible, as many times as you can.
There are 3 sign changes. So the possible positive roots are either 3 or 1.
Now look for the negative possibilities. Replace each x with a -x and then count the sign changes. Replacing with -x's gives you this polynomial:
There is only one sign change here, so the possible negative roots is 1. Start with the negative roots to find the possible combinations of positive, negative, and imaginary, since there is only 1.
- 1 1
+ 3 1
i 0 2
Since this is a 4th degree, the number of roots we have has to add up to equal 4.