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77julia77 [94]
3 years ago
10

Find the distance between the two points in simplest radical form HELP​

Mathematics
1 answer:
GaryK [48]3 years ago
7 0

Given:

The two points on the graph.

To find:

The distance between the two points in simplest radical form.

Solution:

From the given graph, it is clear that the two points on the graph are (-9,3) and (-3,-2).

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, the distance between two points (-9,3) and (-3,-2) is:

d=\sqrt{(-3-(-9))^2+(-2-3)^2}

d=\sqrt{(-3+9)^2+(-5)^2}

d=\sqrt{(6)^2+(-5)^2}

On further simplification, we get

d=\sqrt{36+25}

d=\sqrt{61}

Therefore, the distance between the given points is \sqrt{61} units.

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DerKrebs [107]

Answer:

y = 2x + 2

Hope you have a great day!

7 0
3 years ago
PLS HELP ME this is due today thank u.
Thepotemich [5.8K]

Answer:

True, True, False, True

Hope this helps you!

6 0
3 years ago
Read 2 more answers
This last one I need help on too
ExtremeBDS [4]

Answer:

x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}

Step-by-step explanation:

simplify \frac{-3}{x-2} by putting the negative sign on the outside. \frac{2x}{x-1}-\frac{2x-5}{x^2-3x+2}=-\frac{3}{x-2}

find the LCM of the denominators. It is (x-1)(x-2). Multiply by the LCM:

\frac{2x}{x-1}\left(x-1\right)\left(x-2\right)-\frac{2x-5}{x^2-3x+2}\left(x-1\right)\left(x-2\right)=-\frac{3}{x-2}\left(x-1\right)\left(x-2\right)

Simplify:

2x\left(x-2\right)-\left(2x-5\right)=-3\left(x-1\right)

solve: x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}

3 0
3 years ago
Graph the line that represents this equation:<br> y = -5.1 +2
Mrac [35]
That's for the equation I got from the picture

4 0
3 years ago
Let f (x) = -1/2(x + 2)+ 5
bogdanovich [222]

Answer:

Rate of change = -1

Step-by-step explanation:

Given:

f(x) = -½(x + 2)² + 5

Required:

Average rate of change from x = -3 to x = 1

Solution:

Rate of change = \frac{f(b) - f(a)}{b - a}

Where,

a = -3,

f(a) = f(-3) = -½(-3 + 2)² + 5 = -½(-1)² + 5 = 4.5

b = 1,

f(b) = f(1) = -½(1 + 2)² + 5 = -½(9) + 5 = 0.5

Plug in the values into the formula:

Rate of change = \frac{0.5 - 4.5}{1 - (-3)}

Rate of change = \frac{-4}{4}

Rate of change = -1

8 0
3 years ago
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