There are many ways you can go about doing this. One example is 430÷2=215. I am assuming you are doing multiplication at this time, or you have a calculator nearby. A way you would solve this is choosing a number between 200 and 250, then multiply that by "x"(any number you so choose). The number you would get is "y"(the product of x×your number between 200 and 250). Your equation would then be y÷x=number you choose between 200-250
0.49 is the answer because that is <span>the approximate probability</span>
Given:
Perimeter of rectangular swimming pool = 84 meters
Width of pool = 3/4 of the length
Let's find the length and width of the pool.
Since the swinning pool has the shape of a rectangle and we have the perimeter, to find the length and width, apply the perimeter of a rectangle formula:
![\text{Perimeter = 2(L + W)}](https://tex.z-dn.net/?f=%5Ctext%7BPerimeter%20%3D%202%28L%20%2B%20W%29%7D)
Where:
L is the length
W is the width.
Given:
W = ¾L
Substitute 84 for perimeter and ¾L for W.
Hence, we have:
![\begin{gathered} P=2(L+W) \\ \\ 84=2(L+\frac{3}{4}L) \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%3D2%28L%2BW%29%20%5C%5C%20%20%5C%5C%2084%3D2%28L%2B%5Cfrac%7B3%7D%7B4%7DL%29%20%5Cend%7Bgathered%7D)
Let's evealuate the equation and solve for L.
We have:
![\begin{gathered} 84=2(L+0.75L) \\ \\ 84=2(1.75L) \\ \\ 84=3.5L \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2084%3D2%28L%2B0.75L%29%20%5C%5C%20%20%5C%5C%2084%3D2%281.75L%29%20%5C%5C%20%20%5C%5C%2084%3D3.5L%20%5Cend%7Bgathered%7D)
Divide both sides by 3.5:
![\begin{gathered} \frac{84}{3.5}=\frac{3.5L}{3.5} \\ \\ 24=L \\ \\ L=24\text{ meters} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B84%7D%7B3.5%7D%3D%5Cfrac%7B3.5L%7D%7B3.5%7D%20%5C%5C%20%20%5C%5C%2024%3DL%20%5C%5C%20%20%5C%5C%20L%3D24%5Ctext%7B%20meters%7D%20%5Cend%7Bgathered%7D)
To solve for the width W, substitute 24 for L in (W=¾L)
![\begin{gathered} W=\frac{3}{4}\times L \\ \\ W=\frac{3}{4}\times24 \\ \\ W=\frac{3\times24}{4} \\ \\ W=\frac{72}{4} \\ \\ W=18\text{ meters} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20W%3D%5Cfrac%7B3%7D%7B4%7D%5Ctimes%20L%20%5C%5C%20%20%5C%5C%20W%3D%5Cfrac%7B3%7D%7B4%7D%5Ctimes24%20%5C%5C%20%20%5C%5C%20W%3D%5Cfrac%7B3%5Ctimes24%7D%7B4%7D%20%5C%5C%20%20%5C%5C%20W%3D%5Cfrac%7B72%7D%7B4%7D%20%5C%5C%20%20%5C%5C%20W%3D18%5Ctext%7B%20meters%7D%20%5Cend%7Bgathered%7D)
Therefore, the length of the swimming pool is 24 meters, while the width is 18 meters.
ANSWER:
Length = 24 meters
Width = 18 meters
To find the area of a trapezoid, we need to know the formula. The formula for the area of a trapezoid is: A = (a+b)h/2, with a and b being the lengths of the bases and h being the height of the trapezoid.
In this particular case, we need to figure out the heights and base lengths, then we can input the values and solve.
The height is 7 yards (because it's the line that makes a right angle when it goes down), and the bases are 4.7 yards and 9.5 yards. Now we can input these values into our formula. The formula becomes:
A = (4.7 + 9.5)*7/2
A = 14.2 * 3.5
That means that our answer is A = 49.7 yd.², or A.