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borishaifa [10]
3 years ago
12

Simplify: 27k^5m^8/(4k^3)(9m^2)

Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0
The answer to your question is 3k^2m^6/4
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HURRY TEACHER DIDN'T PUT ON STUDY GUIDE
Andru [333]

1 step: Place the point of the compass on point M and draw an arc, making sure the width of the compass opening is greater than 1/2MN.

2 step: Place the point of the compass on point N and draw an arc that has the same radius as previous one.

3 step: Connect two points of intersection of drawn arcs. Obtained line will be bisector.

Answer: option D.

5 0
3 years ago
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A video game requires at least 4 points to advance. Each solved puzzle is worth two points. Each solved riddle is worth 1 point.
Gwar [14]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x -----> the number of solved puzzles

y -----> the number of solved riddles

we know that

2x+y \geq 4

The solution of the inequality is the shaded area above the solid line 2x+y=4

The slope of the solid line is negative m=-2

The y-intercept of the solid line is the point (0,4)

The x-intercept of the solid line is the point (2,0)

therefore

The graph in the attached figure

3 0
3 years ago
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The radius of a size 5 soccer ball is approximately 11.5 cm. How many square inches of synthetic leather does it
kakasveta [241]

Answer:

1661.06 cm²

Step-by-step explanation:

From the question given above, the following data were obtained:

Radius (r) = 11.5 cm

Size of synthetic leather needed =?

To know how many square centimetres of synthetic leather needed to cover the ball, we shall determine the area of the ball. This can be obtained as follow:

Radius (r) = 11.5 cm

Pi (π) = 3.14

Area of ball =?

The shape of a ball is spherical in nature. Thus, we shall apply the formula for calculating the area of a sphere. This is illustrated below:

A = 4πr²

A = 4 × 3.14 × 11.5²

A = 4× 3.14 × 132.25

A = 1661.06 cm²

Thus, 1661.06 cm² of synthetic leather needed to cover the ball.

6 0
2 years ago
Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa
Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation  

n=580 represent the random sample taken    

X represent the seafood sold in the country that is mislabeled or misidentified by the people

\hat p=0.25 estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

\alpha=0.01 represent the significance level (no given, but is assumed)    

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204

0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

Part c

A government spokesperson claimed that the sample size was too​ small, relative to the billions of pieces of seafood sold each​ year, to generalize. Is this criticism​ valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

4 0
3 years ago
Tiffany started her homework at 5:20, if it took him 45 minuets to get done, what time did he get finished
never [62]

Answer:

6:05

Step-by-step explanation:

5:20+40= 6:00

6:00+5= 6:05

5 0
3 years ago
Read 2 more answers
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