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Rainbow [258]
3 years ago
9

What's the expanded form 310409

Mathematics
1 answer:
viktelen [127]3 years ago
8 0
In expanded form, 310409 would be 300000+10000+400+9
Unless you want it as
3*100000+1*10000+4*100+9
Or even
3*10^5+1*10^4+4*10^2+9
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Sarah started with 50 dollars in her bank account. Each month, she puts 25 more dollars in her account. The amount of money in d
Basile [38]


D=25m+50

D=(25)(8)+50

D=200+50

D=250

There will be $250 after 8 months.

5 0
3 years ago
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6. To clean his floors, Larry uses a recipe for a homemade cleaner of 1 part lemon juice, 1 part vinegar,
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The 8th grade is selling tickets to the 8th grade formal.The cost per ticket is $15.The decorations and food cost $600,and each
MArishka [77]

Answer:

Step-by-step explanation:

Each ticket is $15.  The number of tickets is what we are trying to solve for.  The class spends a certain amount of money to prepare for the formal.  They hope that the money they make in ticket sales is MORE than what they spend.  The expression that represents the number of tickets at $15 each is 15x, where x is the number of tickets.  They hope that the sales are greater than what they spend, so what we have so far is

15x >

Greater than what, though?  What do they spend?  They spend 600 for the food, so

15x > 600...

but they also have to print a certain, unknown number of tickets at .50 each.  The expression that represents the printing of each ticket is .5x (we can drop the 0; it doesn't change the answer or make it wrong if we drop it off).  So the cost for this affair is the food + the printing.

15x > 600 + .5x

Solve this inequality for x.  Begin by subtracting .5 from both sides to get

14.5x > 600 so

x > 41.3

Because we are not selling (or printing) .3 of a ticket, it's safe to say (and also correct!) that they need to sell (and print) 41 tickets.  If they sell 41 tickets, the profit is found by

15(41) > 600 + .5(41)

615 > 600

This means that at 41 tickets, they make a profit.  At 40 tickets, the inequality looks like this:

15(40) > 600 + .5(40) and

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8 0
3 years ago
In ΔUVW, w = 9 cm, v = 2.2 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Alja [10]

Complete Question

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answer:

16.5°

Step-by-step explanation:

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

We solve using Sine rule formula

a/sin A = b/sin B

We are solving for angle W

∠V=136°

Hence:

22 /sin 136 = 9 /sin W

Cross Multiply

22 × sin W = sin 136 × 9

sin W = sin 136 × 9/22

W = arc sin [sin 136 × 9/2.2]

W = 16.50975°

W = 16.5°

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3 years ago
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36.3 Johns number sub or add or divid or multication
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