Nathan bought a cd for his friend. The length and width of the cd case is 4 18⁄25 inches. What is the area of the cd case?

Mathematics

1 answer:

ale4655 [162]3 years ago

3 0

Answer:

Hence the area of CD bought by Nathan is <em>22.2784 square inches.</em>

Step-by-step explanation:

The length and width of a CD bought by Nathan is $4\frac{18}{25}=\dfrac{118}{25}$ inches.

As CD have the same length and width this means it will be of the shape of a square.

Hence, the area of CD is given by:

Area of CD=length×width

= $4\dfrac{18}{25}\times4\dfrac{18}{25}$

= $\dfrac{118}{25}\times\dfrac{118}{25}$

= $\dfrac{118\times118}{25\times25}$

= $\dfrac{13924}{625}$

= $22.2784$

Hence the area of CD bought by Nathan is 22.2784 square inches.

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