A feasible region is bounded by the constraints: 20 20 4 5 0.25 y x y x y x The objective function is P = 3x + 5y. (a) Graph the feasible region. (b) Find the value of the objective function at each vertex of the feasible region.
(c) What is the minimum value of the objective function, P?
(d) At which vertex point does the minimum value occur?
Show all work. Answer: Math | Graded Assignment | Semester A Test, Part 2 © 2016 K12 Inc.
All rights reserved. Page 2 of 3 Copying or distributing without K12’s written consent is prohibited. (Score for Question 3: ___ of 10 points) 2. In 2010, the population of a town was 8500. The population decreased by 4.5% each year.
(a) Write an equation to find the population of the town t years after 2010.
(b) In what year will the population of the town be 7000? Show your work. Answer:
Math | Graded Assignment | Semester A Test, Part 2 © 2016 K12 Inc. All rights reserved. Page 3 of 3 Copying or distributing without K12’s written consent is prohibited. (Score for Question 2: ___ of 10 points)
3. Consider the function 3 2 f x x x x 3 10 13 20 .
(a) Determine the x-intercepts of f x .
(b) Determine the y-intercept of f x .
(c) Identify a point in between each of the x-intercepts of f x .
(d) Determine the end behavior of f x .
(e) Use the points and end behavior from parts (a) – (d) to graph f x . Label the scale of each axis. Answer:
1 answer:
I think it is C I am just guessing
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Answer:
4/9
Step-by-step explanation:
The denominator is the bottom value of a fraction, therefore we can discount 9/2 1/9 = 2/18. 2/18 is smaller than 3/18 so we can discount 1/9 50/100 = 0.5 5/9 = 0.55555... 0.55555... is greatest than 0.5, therefore we can discount 5/9
Negative exponents mean that you flip the number upside down
so -7^-2 would become 1/-7^2
-7^2 would be 49
so the answer is <em>1/49 </em>
$35.00 x .20 = $7 So the discount would be $7 off of $35, for a final sale price of $28
no it is more than 4x it is 6x