Answer:
55.563
Step-by-step explanation:
Given the following :
Mean(m) point = 73
Standard deviation( sd) = 10.6
Lower 5% will not get a passing grade (those below the 5% percentile)
For a normal distribution:
The z-score is given by:
z = (X - mean) / standard deviation
5% of the class = 5/100 = 0.05
From the z - table : 0.05 falls into - 1.645 which is equal to the z - score
Substituting this value into the z-score formula to obtain the score(x) which seperates the lower 5%(0.05) from the rest of the class
z = (x - m) / sd
-1.645 = (x - 73) / 10.6
-1 645 * 10.6 = x - 73
-17.437 = x - 73
-17.437 + 73 = x
55.563 = x
Therefore, the score which seperetes the lower 5% from the rest of the class is 55.563
Answer:
ggggggggggggggggggggggggggggggg
Option A) Center: (2,5) & Radius=7 is the correct one.
<u>Step-by-step explanation:</u>
The general form of the equation of the circle is given as :
⇒ (x-h)² + (y-k)² = r²
where,
- (h, k) are coordinates of the center point of the circle.
- r is the radius of the circle.
Therefore, you need to compare the given equation with the general equation of the circle.
The given equation of circle is (x-2)² + (y-5)² = 49
From the given equation, it can be determined that
h = 2 and y = 5 and r² = 49
The center (h,k) of the circle is (2,5).
<u>To find the radius r :</u>
⇒ r² = 49
⇒ r = 7
The radius of the circle is 7.
∴ Option A) Center: (2,5) & Radius=7 is the correct one.
