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adell [148]
3 years ago
7

Find the exponential function that satisfies the given conditions:

Mathematics
1 answer:
Nady [450]3 years ago
4 0

Answer:

f(t) = 66·0.995^t

Step-by-step explanation:

You can try t=0 and t=1 in each of the formulas to see which one gives values of 66 and 0.5% less than 66, or 65.67.

The first function has an initial value of 0.5, so is not correct.

The second function gives f(1) = 99, so is not correct.

The third function gives f(1) = 65.67, so is correct.

The fourth function gives f(1) = 66.33, so is not correct.

_____

You can realize that the multiplier will be 0.5% less than 100%, so will be 99.5% = 0.995. This number shows up only in the third selection.

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g100num [7]
F(x)=-3x*4 = 6x^2 +C
8 0
3 years ago
×-2+2×+4+2×-2=180 what does x equal in this equation.
daser333 [38]

Answer:

<u>x = 36</u>

Here's how I got that:

<em>    - Group like terms -</em>

x - 2 + 2x + 4 + 2x - 2 = 180

                    ↓

      5x - 2 + 4 - 2 = 180

                    ↓

              5x = 180

<em>  - Divide both sides by 5 - </em>

<em>         </em>  5x/5 = 180/5

                   ↓

<em>                </em><u><em>x </em></u><u>= 36</u>

<em>~ That's all folks ~</em>

<em>-Siascon</em>

6 0
2 years ago
What is (f + g)(x)?<br> f(x) = -2x^2 <br> g(x) = -2x^2 + 9x
andreyandreev [35.5K]

Answer:

-4x^2+9x

Step-by-step explanation:

Adding boh gives

(f+g)(x)=-2x^2+(-2x^2+9x)

=-2x^2-2x^2+9x

=-4x^2+9x

4 0
3 years ago
Find the probability of picking 4 consonant and 1 vowels when 5 letters are picked (without replacement) from a set of alphabet
Ganezh [65]

The required probability is 0.45

We have total 26 letters in english, of which 21 are consonants and 5 are vowels.

According to the question, we have to select 5 of them of which 4 will be consonants and 1 will be vowel.

Suppose we want to have the vowel in the first selection, so the probability of picking a vowel is equal to the quotient between the number of vowels and the number of total number of letters.

So the probability is 5/26

Now, a letter has been selected, so in the set, we have 25 letters left.

In the next 4 selections, we must select consonants.

In the second selection the probability is 21/25

In the third selection the probability is 20/24

In the fourth selection the probability is 19/23

In the last selection the probability is 18/22

So, the probability is (5/26)×(21/25)×(20/24)×(19/23)×(18/22)

Now, remember that we take that the vowel must be in the first place, but it can be in any five places, so if we add the permutations of the vowel letter we have,

P = 5×(5/26)×(21/25)×(20/24)×(19/23)×(18/22) = 0.45

Learn more about probability here :

brainly.com/question/251701

#SPJ10

5 0
1 year ago
Approximate the distance between (1,2) and (7, 6) to the nearest tenth.
viva [34]

Check image below for answer!

4 0
2 years ago
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