If you graph the two equations then you will find that they intersect at (-2,-2).
You then have to check your answer.
x=4y+6
(-2)=4(-2)+6
-2=-8+6
-2=-2
x-3y=4
(-2)-3(-2)=4
-2+6=4
4=4
Answer:
√95 cm
Step-by-step explanation:
To solve, you need to use the pythagorean theorem, or a^2 + b^2 = c^2
The hypotenuse is the c and let one leg be b. You can write:
a^2 + 7^2 = 12^2
a^2 + 49 = 144
Now, you need to solve for a:
a^2 = 144 - 49
a^2 = 95
a = √95 cm, or about 9.75cm
-2x-y=3 ...(1)
x+2y=4 ...(2)
multiply (2) by 2 and add to (1)
-2x-y+2x+4y=3+8
3y=11
y=11/3
from (2)
x=4-2y=4-2(11/3)
or x=4-(22/3)
=(12-22)/3=-10/3
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
