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This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.
Case 1: Five A's and One B
Total number of letters = 6
Total number of words possible = 
Case 2: Five A's and Two B's
Total number of letters = 7
Total number of words possible = 
Case 3: Five A's and Three B's
Total number of letters = 8
Total number of words possible = 
Total number of possible words will be the sum of all three cases.
Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83
Answer:
x = 14; x = 0
Step-by-step explanation:
(x)(6 + 8) = x²
(x)(14) = x²
14x = x²
14x - x² = 0
(x)(14 - x) = 0
x = 14; x = 0
Answer:
c, Z
Step-by-step explanation:
x+y=4
<u>y+z=5</u>
y=4-x
4-x+z=5
<u>-</u><u>x</u><u>+</u><u>z</u><u>=</u><u>1</u>
z=1+x
Answer:
7.5 hours
Step-by-step explanation:
<u>1 method:</u>
Amber drove at an average speed of 55 mph.
Austin averaged 75 mph per hour.
The difference in speed is 20 mph, this means that each hour Austin drove 20 miles more.
Amber drove 110 miles in 2 hours, then Austin needs 110:2=5.5 hours to catch Amber, so in total after 5.5+2=7.5 hours Austin will catch up Amber.
<u>2 method:</u>
Let t hours be the time Amber was driving, then t-2 hours ia Austin's time.
Amber distance = 55t miles
Austin's distance = 75(t-2) miles
When Austin caught up with Amber, their distances are the same:
