I need a quick briefing over slopes preferably how to graph them

Find the slope of the line passing through the points (-5, 3) and (7, 9)

rodikova [14]

$\sf{\red{Answer}}$

$\sf{m = \frac{1}{2} }$

$\sf{\purple{Explanation}}$

$\sf{m = \frac{y_{2}- y_{1}}{m_{2} - m_{1}} }$

$\sf{m = \frac{9- 3}{7- ( - 5)} }$

$\sf{m = \frac{6}{7 + 5} }$

$\sf{m = \frac{6}{12} }$

$\sf{m = \frac{1}{2} }$

3 0

2 years ago

How many edges does a polyhedron with 28 faces and 40 vertices have calculator?

emmasim [6.3K]

Hey user!

your answer is here..

we know about EULER'S FORMULA, it is a formula used to verify a polyhedron or to calculate the number of faces, vertices or edges.

Euler's formula = F + V - E = 2

given :-

faces = 28, verticies = 50 and edge = ?

we know that F + V - E = 2

therefore 28 + 40 - E = 2

==> 68 - E = 2

==> - E = 2 - 68

==> - E = - 66

==> E = 66

hence, the number of edges of the polyhedron is 66.

cheers!!

6 0

3 years ago

Read 2 more answers

If the gradient of the tangent to

Marizza181 [45]

Answer:

Point A(9, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Anything to the 0th power is 1
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = \sqrt{x}$

$\displaystyle y' = \frac{1}{6}$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y = x^{\frac{1}{2}}$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1}$
Simplify: $\displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}}$
[Derivative] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{1}{2x^{\frac{1}{2}}}$
[Derivative] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y' = \frac{1}{2\sqrt{x}}$

Step 3: Solve

Find coordinates of A.

x-coordinate

Substitute in y' [Derivative]: $\displaystyle \frac{1}{6} = \frac{1}{2\sqrt{x}}$
[Multiplication Property of Equality] Multiply 2 on both sides: $\displaystyle \frac{1}{3} = \frac{1}{\sqrt{x}}$
[Multiplication Property of Equality] Cross-multiply: $\displaystyle \sqrt{x} = 3$
[Equality Property] Square both sides: $\displaystyle x = 9$