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3 years ago

Which is the graph of the function f(x)=x^3+x^2+x+1

Mathematics

1 answer:

34kurt3 years ago

3 0

Answer:

Step-by-step explanation:

Next time, please share the possible answers (which here are graphs).

f(x)=x^3+x^2+x+1 builds upon the cubing function x^3, which starts in Quadrant III and continues into Quadrant I. f(x)=x^3+x^2+x+1 displays the same behavior. Note that if x = 0, f(0) = 1, so the y-intercept is (0, 1).

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Write the equation using function notation f(x). then find f(0)<br><br> 2x^2 - 3y = 6

Grace [21]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: f(0) = -2$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: 2 {x}^{2} - 3y = 6$

$\qquad \tt \rightarrow \: 3y + 6 = 2 {x}^{2}$

$\qquad \tt \rightarrow \: 3y = 2 {x}^{2} - 6$

$\qquad \tt \rightarrow \: y = \cfrac{2 {x}^{2} - 6 }{3}$

$\qquad \tt \rightarrow \: y = \cfrac{2 {}^{} }{3} {x}^{2} - 2$

[ here, y can be replaced with f(x) because y is a function of x ]

$\qquad \tt \rightarrow \: f(x) = \cfrac{2 {}^{} }{3} {x}^{2} - 2$

$\large\textsf{Find f(0):}$

$\qquad \tt \rightarrow \: f(0) = \cfrac{2 {}^{} }{3} {(0)}^{2} - 2$

$\qquad \tt \rightarrow \: f(0) = 0 - 2$

$\qquad \tt \rightarrow \: f(0) = - 2$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

1 year ago

Can someone please help me with this!!

miv72 [106K]

Hello there! Given the expression, we can solve through a series of steps:

1. Simplify

-5 + 7 • 1

2. Multiply (according to order of operations)

7 • 1 = 7

3. Add

-5 + 7 = 2

Your final answer is 2. Hope this helps!

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1 year ago

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Step-by-step explanation: