Answer:
5/6
Step-by-step explanation:
slope = 4-(-1)/8-2 = 5/6
Answer:
<u><em></em></u>
- <u><em>Event A: 1/35</em></u>
- <u><em>Event B: 1/840</em></u>
<u><em></em></u>
Explanation:
<u>Event A</u>
For the event A, the order of the first 4 acts does not matter.
The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.
Thus, the number of ways that the first <em>four acts</em> can be scheduled is:
![C(m,n)=\dfrac{m!}{n!(m-n)!}](https://tex.z-dn.net/?f=C%28m%2Cn%29%3D%5Cdfrac%7Bm%21%7D%7Bn%21%28m-n%29%21%7D)
![C(7,4)=\dfrac{7!}{4!(7-4)!}=\dfrac{7!}{4!(3)!}=35](https://tex.z-dn.net/?f=C%287%2C4%29%3D%5Cdfrac%7B7%21%7D%7B4%21%287-4%29%21%7D%3D%5Cdfrac%7B7%21%7D%7B4%21%283%29%21%7D%3D35)
And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).
Therefore the<em> probability of Event A</em> is:
![P(A)=1/35](https://tex.z-dn.net/?f=P%28A%29%3D1%2F35)
Event B
Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.
The number of ways in which <em>four acts </em>can be scheculed when the order matters is:
![P(m,n)=\dfrac{m!}{(m-n)!}](https://tex.z-dn.net/?f=P%28m%2Cn%29%3D%5Cdfrac%7Bm%21%7D%7B%28m-n%29%21%7D)
![P(m,n)=\dfrac{7!}{(7-4)!}=P(m,n)=\dfrac{7!}{4!}=840](https://tex.z-dn.net/?f=P%28m%2Cn%29%3D%5Cdfrac%7B7%21%7D%7B%287-4%29%21%7D%3DP%28m%2Cn%29%3D%5Cdfrac%7B7%21%7D%7B4%21%7D%3D840)
The number of ways <em>the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth</em> is 1: P(4,4)
Therefore, <em>the probability of Event B</em> is:
![P(B)=1/840](https://tex.z-dn.net/?f=P%28B%29%3D1%2F840)
Answer:
9q+4z+12
Step-by-step explanation:
Answer:
GCF 4, LCM 80
Step-by-step explanation:
Since both 16 and 20 have two 2s as factor, their greatest common factor is 4.
The LCM is found by multiplying all of the remaining factors by the LCM:
16 still has (2 x 2), 20 still has (5), times the GCF (4) so 2 x 2 x 5 x 4 = 80.