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3 years ago

How to solve how many 3/4s are in 2 with multiplication

Mathematics

1 answer:

ASHA 777 [7]3 years ago

7 0

Answer:

If you divide first (2 ÷ 3/4) just multiplu when you check your math.

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Verify that a+b=b+a by taking a=6 and b=3/6

Klio2033 [76]

Answer:

Step-by-step explanation:

substitute all the numbers in

6+3/6+3/6+6=13

4 0

3 years ago

Where do I find my work I did with a tutor?

OlgaM077 [116]

It should come up as a notification. Check your messages or press “tutor” maybe even try reloading the page.

8 0

2 years ago

Which part is which from the circle

gizmo_the_mogwai [7]

<h3>Check out the diagram below for the proper labeling</h3>

The radius goes from the center to the edge of the circle.

The diameter is twice as long as the radius; it is a segment going through the center with both endpoints on the circle

The circumference is the distance around the circle. Think of it as the perimeter of the circle.

3 0

2 years ago

please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me

mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH= $\sqrt{(5-0)^{2}+(1-1)^{2}}=5$ and

GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$

Now, mid point of JH= $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

= $(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)$

Mid point of GI= $(\frac{5}{2},1)$

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

$(GI)^{2}=(IJ)^{2}+(JG)^{2}$ (1)

Now, JI= $\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20}$ and GJ= $\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}$

Substituting these values in (1), we get

$5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }$

$25=20+5$

$25=25$

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$ and HJ= $\sqrt{(0-5)^2+(1-1)^2}=5$ are equal, thus, GHIJ is a rectangle.

6 0

2 years ago

What is the place value for 9 and 7 for the number 12354897

icang [17]

7 is in the ones place value.
9 is in the tens place value.

Hope this helps.
-Benjamin

7 0

3 years ago