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mamaluj [8]
3 years ago
5

Graph the first six terms of a sequence where a1=5 and r=1.25

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0
The sequence above is geometric progression. 
The nth term of such sequence is given by;

Tn = ar∧(n-1),
Where a⇒first term and
            r⇒common ratio

So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5 
      2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
      3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
       4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
       5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
       6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909
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#1:Proportional Medians Theorem


#2:BD/FH = CB/GF


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So the first ratio is 3/2 because both are divisible by 8. the ratio stays 3/2. 3*9=27. so 2*9=18


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