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mamaluj [8]
3 years ago
5

Graph the first six terms of a sequence where a1=5 and r=1.25

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0
The sequence above is geometric progression. 
The nth term of such sequence is given by;

Tn = ar∧(n-1),
Where a⇒first term and
            r⇒common ratio

So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5 
      2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
      3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
       4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
       5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
       6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909
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Evaluate the function y=1/2(x)-4 for each of the given domain values? PLZ HELP ME
erik [133]

Answer:

c. -13/4.

d. -13/3.

Step-by-step explanation:

c. f(3/2) = (1/2)(3/2) - 4

= 3 / 4 - 4

= 0.75 - 4

= -3.25

= -3 and 1/4

= -13/4.

d. f(-2/3) = (1/2)(-2/3) - 4

= -2/6 - 4

= -1/3 - 4

= -1/3 - 12/3

= -13/3.

Hope this helps!

6 0
3 years ago
X2-7x-18÷x2+8x+12 what is it in lowest terms
Eddi Din [679]

\dfrac{x^2-7x-18}{x^2+8x+12}=\dfrac{x^2+2x-9x-18}{x^2+6x+2x+12}=\dfrac{x(x+2)-9(x+2)}{x(x+6)+2(x+6)}\\\\=\dfrac{(x+2)(x-9)}{(x+6)(x+2)}=\dfrac{x-9}{x+6}

5 0
3 years ago
Ali ran 3/10 km before school after school she ran 1/5 km
miss Akunina [59]

Answer:

1/2 km

Step-by-step explanation:

3/10 + 1/5, find common denominators

3/10 + 2/10 = 5/10, simplify

1/2 km

8 0
3 years ago
Write the log equation as an exponential equation. You do not need to solve for x.
V125BC [204]

Answer:

(x-6)^3x-5 =6

Step-by-step explanation:

logb a=c ------>  b^c =a

7 0
3 years ago
The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)
Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}

Now, we have to find the quotient of the above expression.

So, here we go:

Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)

Now, we will divide the above simplest form with g(x):

\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2

Hence, the quotient is (x-2).


6 0
3 years ago
Read 2 more answers
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