A 120 watt light-bulb is a 0.120 kilowatt light bulb.
In one hour, it uses 0.120 kilowatt-hour of energy.
If electrical energy costs $0.20 per kilowatt hour, then that light bulb costs
(0.120 kilowatt-hour / hour) x (0.20 dollar / kilowatt-hour) =
(0.120 x $0.20 / hour) =
$0.024 / hour = <span>2.4¢ per hour </span>
Answer:
D. ![\sqrt[3]{5^7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E7%7D)
Step-by-step explanation:
The formula for this conversion is:
![a^\frac{x}{n}=\sqrt[n]{a^x}](https://tex.z-dn.net/?f=a%5E%5Cfrac%7Bx%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Ba%5Ex%7D)
Substitute the values you currently have.
![5^\frac{7}{3}=\sqrt[n]{a^x}](https://tex.z-dn.net/?f=5%5E%5Cfrac%7B7%7D%7B3%7D%3D%5Csqrt%5Bn%5D%7Ba%5Ex%7D)
Since we know that
a = 5
x = 7
n = 3
Fill the square root with this.
![5^\frac{7}{3}=\sqrt[3]{5^7}](https://tex.z-dn.net/?f=5%5E%5Cfrac%7B7%7D%7B3%7D%3D%5Csqrt%5B3%5D%7B5%5E7%7D)
Answer:
g^5h^2
Step-by-step explanation:
12g^5h^4, g^5h^2
This is one way of doing it. Break down every number and every variable into a product of the simplest factors. Then see how many of each factor appear in both monomials.
12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h
g^5h^2 = g * g * g * g * g * h * h
So far you see every single prime factor of each monomial.
Now I will mark the ones that are present in both. Those are the common factors.
12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h
g^5h^2 = g * g * g * g * g * h * h
The greatest common factor is the product of all the factors that appear in both monomials.
GCF = g * g * g * g * g * h * h = g^5h^2
$285×15/100
= $42.75 and this is the discount
$285-42.75 = $242.25
Sally will buy the bicycle at $ 242.25
20% of 123.74 can be represented like so:
123.74 * (20/100)
Which is
123.74 * (1/5)
Which is
123.74 ÷ 5
Which equals your answer,
24.748
