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Jobisdone [24]
3 years ago
12

There are 220 students in Year 7. 15% cycle to school. 60% are driven to school. The rest walk to school. (a) How many students

cycle to school? (b) How many students are driven to school? (c) How many students walk to school?
​
Mathematics
2 answers:
Paha777 [63]3 years ago
7 0

Answer:

cycle=33 students, driven=132 students, walk=55 students

Step-by-step explanation:

<h2>solution</h2><h2>60+15+x=100 to get the remaining percentage</h2><h2>x=25</h2><h2>15÷100×220=33</h2><h2>60÷100×220=132</h2><h2>25÷100×220=55</h2>
mr_godi [17]3 years ago
7 0

Answer:

a) 33 students cycle to school

b) 132 students are driven to school

c) 55 students walk to school

Step-by-step explanation:

<h2><u>Finding the number of students that arrive to school by different means of transport.</u></h2><h2><u /></h2><h3><u> Question (a) How many students cycle to school?</u></h3>

<em>since 15 % of the students cycle to school :</em>

15% * 220 students

<u>=33</u>

<h3><u>hence 33 students cycle to school</u></h3>

<u />

<h3><u>Question (b) How many students are driven to school?</u></h3>

<em>since 60 % of the students are driven to school</em>

60% * 220 students

<u>= 132</u>

<h3><u>hence 132 students are driven to school.</u></h3>

<u />

<h3><u>Question (c) How many students walk to school?</u></h3>

since the remaining students walk to school . <em>we can find this by removing the number of students that cycle and are driven to school from the total amount of students in the school.</em>

33 students walk to school

132 students are driven to school

the remaining students walk to school

= 220 - 33 - 132

<u>= 55</u>

<h3><u>hence 55 students walk to school. </u></h3>

<u />

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Given that G=ab find the percentage increase in G when both a and b<br> increase by 10%
monitta

The percentage change in G is 21 %

<h3>What is Percentage change ?</h3>

Percentage change is defined as the increase or decrease in the value as compared to the original value multiplied by 100.

It is given that

G = ab

when a is increased by 10% the new a will be = 1.1 a

When b is increased by 10% the new b will be 1.1 b

So,

G' = 1.1a *1.1 b

G' = 1.21 ab

G' = 1.21

(G' - G)*100/G = (1.21-1)*100/1

The percentage change is 21 %

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2 years ago
Which statement best illustrates using the vertical line test to determine if the graph below is a function of x ?
kirill115 [55]

If something is a function, every x-value, only has one (1) y-value. If the line x = 0 intersects the graph in two points, there are to values for y (instead of one). Therefore the graph is not a function of x.


Your answer is A.


4 0
3 years ago
Read 2 more answers
Please help me!
RUDIKE [14]

Answer:

B. 1/9

Step-by-step explanation:

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Answer:

P(7, -7)

Step-by-step explanation:

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3 years ago
A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f
mestny [16]

Answer:

The value is W= 2640 \  ft \cdot lb

Step-by-step explanation:

From the question we are told that

The weight of the bucket is F =  5 lb

The depth of the well is x_1 =  60 \ ft

The weight of the water is W_w  =  42 lb

The rate at which the bucket with water is pulled is v  = 1.5 \  ft/s

The rate of the leak is r = 0.15 lb/s

Generally the workdone is mathematically represented as

W =  \int\limits^{x_1}_{x_o} {G(x)} \, dx]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

G(x) =  F  +  (W_w- Ix)

Here I is the rate of water loss in lb/ft mathematically represented as

I  = \frac{r}{v}

=> I  = \frac{0.15 }{1.5 }

=> I  = 0.1

So

G(x) =  5  +  (42- 0.1x)

=> G(x) =  47- 0.1x)

So

W =  \int\limits^{60}_{0} {47- 0.1x} \, dx]

=> W =  [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.

=> W= [47(60) - 0.05(60)^2]

=> W= 2640 \  ft \cdot lb

7 0
3 years ago
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