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evablogger [386]
3 years ago
8

Given that the points (-5, 7), (5, 7), (5, 1), and (-5, 1) are vertices of a rectangle, how much shorter is the width than the l

ength?
A) -5 units
B) -4 units
C) -3 units
D) -2 units
Please answer ASAP and will mark as Brainliest!
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
5 0
B. -4 units
if i did the math right
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Answer:

50% 250x2=450

Step-by-step explanation:

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1.What are the zeros of the polynomial function?
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Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

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Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
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c = -60

Delta = b^2 -4ac

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Delta = 16 + 240

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Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

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Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
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Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

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Then we stayed with:

x = [ -b +/- √Delta ]/2a

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We wiil have two possibilities

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Or

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To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
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Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

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Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

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That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9


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