6= mx+b
6-b=mx
x=(6-b)/m
hope you understand
Step-by-step explanation:
A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :
f(t) = -32 t+285
Height of the ball is :

C is constant. Here the ball is launched from a height of 6 feet. So,

At t = 2 s, 
At t = 9 s, 
Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.
Answer: 6x+3y
Step-by-step explanation:
3x+3(x+y)= 3x+3x+3y=6x+3y
Answer: m∠BCE = 63°
m∠BAD = 76°
Step-by-step explanation:
Problem 1:
Given
m∠BEC = 90°
m∠EBC = 27°
Total = 117°
Solution:
Subtract 180° - 117° = m∠BCE = 63°
Problem 2:
Given
m∠ADE = 52°
m∠ABE = 52°
Total = 104°
Solution:
Subtract 180° - 104° = m∠BAD = 76°
The first one is the answer to the question