I thnk 83 if the year has 365 days
Y=14x
Compare with general form:
y=kx
Where k is the constant of proportionality.
Here k=14
So 1 unit increase in x will bring 14 times increase in y.
There is a direct relation between x and y.
Answer: Yes
Line BE and KE are the same length, so set the 2 equations to equal and solve for P.
7p+7 = 37-3p
Add 3 p to both sides:
10p +7 = 37
Subtract 7 from each side:
10p = 30
Divide both sides by 10:
p = 30/10
p = 3
The answer is B.
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
7(x-2) +3x=46
7x-14+3x=46
10x-14=46
10x=60
X=6