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KengaRu [80]
3 years ago
15

A bookstore has a sale: Jen wants to buy four books: for $10.00, for $12.00, for $15.00, and for $20.00. What is the smallest sh

e could pay for these books during the sale? By what percent would the sale reduce the total cost of these four books?

Mathematics
1 answer:
kolezko [41]3 years ago
6 0

Answer:

$47, 17.5%

Step-by-step explanation:

When she buys the $20 book, she can get 40% off either the $15, $12, or $10 book.  She'll save the most by getting 40% off the $15 book.

Then, when she buys the $12 book, she'll get %40 off the $10 book.

The total she pays is:

20 + (0.60)(15) + 12 + (0.60)(10)

20 + 9 + 12 + 6

47

Without the discounts, the cost of the books would have been:

20 + 15 + 12 + 10

57

So she saves $10.  10 out of 57 is approximately 17.5%.

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3 years ago
Does the equation y=14x represennt a proportinal relationship?
Sonbull [250]
Y=14x
Compare with general form:
y=kx
Where k is the constant of proportionality.
Here k=14
So 1 unit increase in x will bring 14 times increase in y.
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Answer: Yes
5 0
3 years ago
Geometry math question please help
Pie

Line BE and KE are the same length, so set the 2 equations to equal and solve for P.

7p+7 = 37-3p

Add 3 p to both sides:

10p +7 = 37

Subtract 7 from each side:

10p = 30

Divide both sides by 10:

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8 0
3 years ago
Read 2 more answers
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
1. 8x – 4 = 12x + 12
olga_2 [115]
7(x-2) +3x=46
7x-14+3x=46
10x-14=46
10x=60
X=6
3 0
3 years ago
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