The product of two even numbers is even.
Let m and n be any integers so that 2m and 2k are two even numbers.
The product is 2m(2k) = 2(2mk), which is even.
Things to think about:
Why didn’t I just show you by using any two even numbers like the number 4 and the number 26?
Why did I change from "m" to "k" ? Are they really different numbers or could they be the same?
Why did I specifically say that m and k were integers?
The product of two odd numbers is an odd number.
Let m and k be any integers. This means that 2m+1 and 2k+1 are odd numbers.
The product is 4mk + 2m + 2k + 1 (hint: I used FOIL) which can be written as
2 ( 2mk + m + k ) + 1 which is an odd number.
Equation of a circle that has a center at (h,k) and radius of r is
(x-h)²+(y-k)²=r²
so
given center (-1,2)
(x-(-1))²+(y-2)²=r²
(x+1)²+(y-2)²=r²
sub the other point to find r or r²
it passes through (2,-2)
sub 2 for x and -2 for y
(2+1)²+(-2-2)²=r²
(3)²+(-4)²=r²
9+16=r²
25=r²
5=r
the equation is
(x+1)²+(y-2)²=5²
Answer: (y - 2) (y -3)
Step-by-step explanation:
The answer is 45 :^))))))))))
Answer:
238cm³
Step-by-step explanation:
