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sesenic [268]
3 years ago
12

If the probabilities that an automobile mechanic will service 3, 4, 5, 6, 7, or 8 or more cars on any given workday are, respect

ively, 0.12, 0.19, 0.28, 0.24, 0.10, and 0.07, what is the probability that he will service at least 5 cars on his next day at work?
Mathematics
1 answer:
Readme [11.4K]3 years ago
5 0

Answer:

P(X\geq 5)=0.69

Step-by-step explanation:

We need to find the probability that the mechanic will service  or more cars.

It's a simpler one given that we have the probabilities of servicing 4 or less cars.

P(at least 5 cars) is given by subtracting the probabilities of servicing both 3 and 4 cars.

P(X\geq 5)=1-p(x=4)-p(x=3)\\P(X\geq5)=1-0.12-0.19\\P(X\geq5)=1-0.31\\=0.69

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Read 2 more answers
(x + 5 1/2) 0.75= 5/8 What is x?
swat32
<span>(x + 5 1/2) 0.75= 5/8<span>
Convert 0.75 into a fraction
</span></span><span>(x + 5 1/2) 3/4= 5/8
Use distributive property
3/4x + 5 1/2*3/4 = 5/8
Convert 5 1/2 into improper fraction
3/4x + 11/2*3/4 = 5/8
Multiply
3/4x + 33/8 = 5/8
Subtract 33/8 from both sides
3/4x = 5/8 - 33/8
Subtract the numerators but NOT the denominators
3/4x = -28/8
Divide 3/4 on both sides
x = -28/8 divided by 3/4
Convert the division sign to multiplication while flipping the fraction 3/4 to 4/3
x = -28/8 * 4/3
Multiply
Final Answer: x = -112/24 or -4 16/24 or -4 4/6 or -4 2/3 *All answers are equivalent to each other.</span>
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Are all trapezoids quadrilaterals
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