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soldi70 [24.7K]
3 years ago
10

MN bisects PQ at point R. Which of the following is true about point R?

Mathematics
2 answers:
makvit [3.9K]3 years ago
8 0

yes B is right i would have to go with u on that one yes

FrozenT [24]3 years ago
7 0
The correct answer for this would be B
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Illusion [34]
I’m not sure but maybe true
3 0
3 years ago
Half the difference between two numbers is 2. The sum of the
leva [86]

Answer:

as below

Step-by-step explanation:

1st  the difference is 4  b/c half of 4 = 2

and

2*smaller +greater = 13

so check out small number that are 4 apart.. like 2 and 6

2(2)+6 =10

2(3) +7 = 13  aahh hah..  that's it

3 and 7 are the numbers being hunted :P

5 0
3 years ago
What is the center of the ellipse x2+5y2–45=0?
jeka94

Answer:

Center is at (0,0)

Step-by-step explanation:

An equation of ellipse in standard form is:

\displaystyle{\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2} = 1

Where center is at point (h,k)

From the equation of \displaystyle{x^2+5y^2-45=0}. First, we add 45 both sides:

\displaystyle{x^2+5y^2-45+45=0+45}\\\\\displaystyle{x^2+5y^2=45}

Convert into the standard form with RHS (Right-Hand Side) equal to 1 by dividing both sides by 45:

\displaystyle{\dfrac{x^2}{45}+\dfrac{5y^2}{45}=\dfrac{45}{45}}\\\\\displaystyle{\dfrac{x^2}{45}+\dfrac{y^2}{9}=1}

Therefore, the center of ellipse is at (0,0) since there are no values of h and k.

8 0
2 years ago
Kate says negative numbers are integers. What is her error
igor_vitrenko [27]
Integers can only be whole numbers, so she should have said that negative WHOLE numbers are integers.
3 0
3 years ago
Will vote brainliest. Thanks!!!
AVprozaik [17]
I believe that the answer to your question is B !
8 0
3 years ago
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