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3 years ago

Xy + 3ey = 3e, find the value of y'' at the point where x = 0.

2 answers:

7 0

y might be 1 and I got that cuz 0y+3ey=3e and replace y with 1 and you get 0•1+3e•1=3e and to be honest it kinda looks like it makes sense

n200080 [17]3 years ago

3 0

Answer: y = 1

Step-by-step explanation:

If the equation is:

x*y + 3*e^y = 3*e

where x and y are variables, and e is a real number, we have that when x = 0, the value of y must be:

0*y + 3*e^y = 3*e

3*e^y = 3*e

(3*e^y)/(3*e) = 1

e^(y - 1) = 1

we know that any number A, when we have A^0 = 1

so here we have that y must be equal to 1

so y = 1

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(A) Write an expression for a number that is five <br> times greater than two

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5x+2 because you have to multiply 5 by x and then add two

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4 years ago

Solve by factoring the equation x^2+36=12x

Fudgin [204]

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4 years ago

who else has trouble with math and then gets ridiculed and made fun of by teachers and adults and other, smarter students and th

melomori [17]

Answer:

'''who else has trouble with math and then gets ridiculed and made fun of by teachers and adults and other, smarter students and then just wants to die?''

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3 0

3 years ago

Read 2 more answers

Is this right ? Im honestly confused

fgiga [73]

Answer:

In step by step

Step-by-step explanation:

For #1, everything is perfect.

For #2, you wrote your functions out incorrectly, but your x input and y output are correct

#3 is a little messed up.

Your function is f(x)=-3x+1. Your given x's are -3, -1, 0, 1, 2, and 3. Plug all of these in.

1. f(-3)=-3(-3)+1

f(-3)=9+1
f(-3)=1

2. f(-1)=-3(-1)+1

f(-1)=3+1
f(-1)=4

3. f(0)=-3(0)+1

f(0)=0+1
f(0)=1

4. f(1)=-3(1)+1

f(1)=-3+1
f(1)=-3

5. f(2)=-3(2)+1

f(2)=-6+1
f(2)=-5

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3 years ago

The graph of the function y = x^2 - x -2

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I hope this graph helps

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3 years ago