Xy + 3ey = 3e, find the value of y'' at the point where x = 0.
2 answers:
y might be 1 and I got that cuz 0y+3ey=3e and replace y with 1 and you get 0•1+3e•1=3e and to be honest it kinda looks like it makes sense
Answer: y = 1
Step-by-step explanation:
If the equation is:
x*y + 3*e^y = 3*e
where x and y are variables, and e is a real number, we have that when x = 0, the value of y must be:
0*y + 3*e^y = 3*e
3*e^y = 3*e
(3*e^y)/(3*e) = 1
e^(y - 1) = 1
we know that any number A, when we have A^0 = 1
so here we have that y must be equal to 1
so y = 1
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