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3 years ago

Xy + 3ey = 3e, find the value of y'' at the point where x = 0.

2 answers:

7 0

y might be 1 and I got that cuz 0y+3ey=3e and replace y with 1 and you get 0•1+3e•1=3e and to be honest it kinda looks like it makes sense

n200080 [17]3 years ago

3 0

Answer: y = 1

Step-by-step explanation:

If the equation is:

x*y + 3*e^y = 3*e

where x and y are variables, and e is a real number, we have that when x = 0, the value of y must be:

0*y + 3*e^y = 3*e

3*e^y = 3*e

(3*e^y)/(3*e) = 1

e^(y - 1) = 1

we know that any number A, when we have A^0 = 1

so here we have that y must be equal to 1

so y = 1

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$\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}$

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$\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}$

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2 years ago