Try this: Principal times (1+interest rate as a decimal fraction)^(number of yrs)
In this case, Principal = $28,000; interest rate = -0.25; # of years = 1
So Decrease in value = $28,000 (0.75)^1 = $21,000.
Answer:
x=1
Step-by-step explanation:
I am pretty sure the answer is 2,520.
Answer:
Yes, we can assume that the percent of female athletes graduating from the University of Colorado is less than 67%.
Step-by-step explanation:
We need to find p-value first:
z statistic = (p⁻ - p0) / √[p0 x (1 - p0) / n]
p⁻ = X / n = 21 / 38 = 0.5526316
the alternate hypothesis states that p-value must be under the normal curve, i.e. the percent of female athletes graduating remains at 67%
H1: p < 0.67
z = (0.5526316 - 0.67) / √[0.67 x (1 - 0.67) / 38] = -0.1173684 / 0.076278575
z = -1.538681
using a p-value calculator for z = -1.538681, confidence level of 5%
p-value = .062024, not significant
Since p-value is not significant, we must reject the alternate hypothesis and retain the null hypothesis.
23 Pennie’s is the answer I believe
