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scoray [572]
3 years ago
14

If f(x)=x/2+8, what is(fx) when x=10

Mathematics
2 answers:
Serjik [45]3 years ago
4 0

Answer:

13

Step-by-step explanation:

f(x) =  \frac{x}{2}  + 8 \\ plug \: x = 10 \\ f(10) =  \frac{10}{2}  + 8 \\  f(10) = 5 + 8 \\ f(10) = 13 \\  \implies \: f(x) = 13 \\

andrey2020 [161]3 years ago
3 0

Answer:

<h2>13</h2>

Solution,

f(X)=\frac{x}{2}  + 8

X = 10 (Given)

Now,

finding the value of f(x) when X = 10

f(X)=\frac{x}{2}  + 8

Plugging the value of X

f(10)=\frac{10}{2}  + 8

\frac{10 + 8 \times 2}{2}

\frac{10 + 16}{2}

\frac{26}{2}

13

Hope this helps....

Good luck on your assignment...

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A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.
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Answer:

a. 39.55%

b. 44.02%

Step-by-step explanation:

We have the following data:

n = 5

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to. If the sampling is done with replacement.

We apply the binomial distribution formula, which is as follows:

P = nCx * (p ^ x) * ((1-p) ^ (n-x))

Where nCx, is a combination, and is equal to:

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replacing we have:

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b. if the sampling is done without replacement.

Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

5C1 = 5! / 1! * 4! = 5

the second is when n = 20 and x = 5, this is all possible scenarios.

20C5 = 20! / 5! * 15! = 15504

and the third is when n = 15 (20-5) and x = 4 (5-1), which corresponds to the cases when none were damaged

15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

P = (5C1 * 15C4) / 20C5

Replacing:

P = 5 * 1365/15504

P = 0.4402

Which means that without replacing the probability is 44.02%

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