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3 years ago

7

If the scale on a map is 1 cm for every 117 km and Washington, D.C., and Baghdad, Iraq, are 85.26 cm apart on the map, then appr

oximately how far apart are they really?

1 answer:

belka [17]3 years ago

5 0

If 1 cm represents 117 Km.

Then, 85.26 cm represents 117×85.26=9975.42 Km

therefore, the given places are 9975.42 Km apart from eachother.

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Zack has a old car. He wants to sell it for 60% off the current price. The market price is $500. How much money would he receive

Snowcat [4.5K]

Zack would receive $200. You have to make 60% as a decimal= 0.60 then multiply $500*0.60= $300 then you subtract $500-$300=$200
(Hope this works!!)

6 0

3 years ago

Please help me with this!

DochEvi [55]

Answer:

10 is real, rational, integer, whole, natural

5/6 is real, rational

sqrt of 24 is real, irrational

0 is real, rational, integer, whole

sqrt 81 is real, rational, integer, whole, natural

Step-by-step explanation:

Classification

6 0

3 years ago

The function f is defined by the following rule

Oxana [17]

Answer:

The answer to your question is given below.

Step-by-step explanation:

1. f(x) = 5x + 1

x = – 5

f(x) = 5x + 1

f(–5) = 5(–5) + 1

f(–5) = –25 + 1

f(–5) = –24

2. f(x) = 5x + 1

x = – 1

f(x) = 5x + 1

f(–1) = 5(–1) + 1

f(–1) = –5 + 1

f(–1) = – 4

3. f(x) = 5x + 1

x = 1

f(x) = 5x + 1

f(1) = 5(1) + 1

f(1) = 5 + 1

f(1) = 6

4. f(x) = 5x + 1

x = 2

f(x) = 5x + 1

f(2) = 5(2) + 1

f(2) = 10 + 1

f(2) = 11

5. f(x) = 5x + 1

x = 2

f(x) = 5x + 1

f(3) = 5(3) + 1

f(3) = 15 + 1

f(3) = 16

Summary

x >>>>>>>> f(x)

–5 >>>>>> – 24

–1 >>>>>> – 4

1 >>>>>>>> 6

2 >>>>>>> 11

3 >>>>>>> 16

8 0

3 years ago

Int(1 \(1 + {e}^{x} )

Andreyy89

Answer:

$\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx}= x - \ln(1 + e^{x}) + C\end{aligned}$ .

Step-by-step explanation:

The first derivative of the denominator $1 + e^{x}$ is $e^{x}$ . Rewrite the fraction to obtain that expression on the numerator.

$\begin{aligned}\frac{1}{1 + e^{x}} &= \frac{1 + e^{x}}{1 + e^{x}} - \frac{e^{x}}{1+e^{x}}\\&=1-\frac{e^{x}}{1+e^{x}}\end{aligned}$ .

In other words,

$\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx} &= \int{dx} - \int{\frac{e^{x}}{1+e^{x}}\cdot dx}\end{aligned}$ .

Apply $u$ -substitution on the integral $\displaystyle \int{\frac{e^{x}}{1+e^{x}}\cdot dx}$ :

Let $u = 1 + e^{x}$ . $u > 1$ .

$du = e^{x}\cdot dx$ .

$\displaystyle \int{\frac{e^{x}}{1+e^{x}}\cdot dx} = \int{\frac{du}{u}} = \ln{|u|} = \ln{u} +C = \ln{(1+e^{x})}+C$ .

Therefore

$\begin{aligned}\int{\frac{1}{1 + e^{x}}\cdot dx} &= \int{dx} - \int{\frac{e^{x}}{1+e^{x}}\cdot dx}\\ & = x - \ln{(1 + e^{x})}+C\end{aligned}$ .

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2 years ago

20 POINTS !!!!!!!!!

mezya [45]

Answer:

x = x = 9 ± $\sqrt{13}$ or x ≈ 12.61 or x ≈ 5.39

Step-by-step explanation:

x² - 18x + 68 Solve by completing the square.

x² - 18x = - 68

Now complete the square and add that number to both sides of the equation.

1/2 (of the coefficient of the x term)² = (1/2 · -18)² = 81 .

x² - 18x + 81 = -68 + 81

(x - 9) (x - 9) = 13 Now find the square root of both sides

$\sqrt{(x - 9)(x - 9)}$ = $\sqrt{13}$ Solve

x - 9 = ± $\sqrt{13}$ Solve for x

x = 9 ± $\sqrt{13}$

x = 9 + $\sqrt{13}$ or x = 9 - $\sqrt{13}$

x ≈ 12.61 or x ≈ x 5.39

6 0

2 years ago