Which expression is equivalent to the area of square A, in square inches?

If y varies directly as the x^2 and y = 200 when x = 5, what is the value of y when x = -3?

gayaneshka [121]

As the variation is direct we have:
$y = kx ^ 2
$
We must find the value of k.
For this, we use the following data:
y = 200 when x = 5
Substituting values we have:
$200 = k5 ^ 2
$
Clearing k:
$k = 200/5 ^ 2

k = 200/25

k = 8$
Then, the function is:
$y = 8x ^ 2
$
We evaluate the function for x = -3
$y = 8 (-3) ^ 2

y = 8 (9)

y = 72$
Answer:
the value of y when x = -3 is:
c.
72

6 0

4 years ago

Evaluate the triple integral_E x^6e^y dV where E is bounded by the parabolic cylinder z = 25 - y^2 and the planes z = 0, x = 5,

Nimfa-mama [501]

Nothing crazy here, just a matter of figuring out the limits of integration.

$\displaystyle\iiint_Ex^6e^y\,\mathrm dV=\int_{-5}^5\int_{-5}^5\int_0^{25-y^2}x^6e^y\,\mathrm dz\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_{-5}^{-5}\int_{-5}^5x^6e^y(25-y^2)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\left(\int_{-5}^5x^6\,\mathrm dx\right)\left(\int_{-5}^5e^y(25-y^2)\,\mathrm dy\right)=\boxed{\frac{625,000(3+2e^{10})}{7e^5}}$

4 0

3 years ago

Assume the readings on thermometers are normally distributed with a mean of 0degreesc and a standard deviation of 1.00degreesc.

Tanzania [10]

Let Z be the reading on thermometer. Z follows Standard Normal distribution with mean μ =0 and standard deviation σ=1

The probability that randomly selected thermometer reads greater than 2.07 is

P(z > 2.07) = 1 -P(z < 2.07)

Using z score table to find probability below z=2.07

P(Z < 2.07) = 0.9808

P(z > 2.07) = 1- 0.9808

P(z > 2.07) = 0.0192

The probability that a randomly selected thermometer reads greater than 2.07 is 0.0192

3 0

4 years ago

Listed below are prices in dollars for one night at different hotels in a certain region. Find the range, variance, and standar

Artyom0805 [142]

Answer:

Range = 115$

Standard Deviation = 43.76$

Variance = 1915.142$

Option A) The measures of variation are not very useful because when searching for a room, low prices, location, and good accommodations are more important than the amount of variation in the area.

Step-by-step explanation:

We are given the data for prices in dollars for one night at different hotels in a certain region.

234, 160, 119, 131, 218, 207, 146, 141

Range:

Sorted data: 119, 131, 141, 146, 160, 207, 218, 234

$\text{Range} = 234-119 = 115\$$

Standard Deviation:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1356}{8} = 169.5$

Sum of squares of differences = 4160.25 + 90.25 + 2550.25 + 1482.25 + 2352.25 + 1406.25 + 552.25 + 812.25 = 13406

$\sigma = \sqrt{\dfrac{13406}{7}} = 43.76\$$

Variance =

$\sigma^2 = 1915.142\$$

Measure of variance for someone searching for room:

Option A) The measures of variation are not very useful because when searching for a room, low prices, location, and good accommodations are more important than the amount of variation in the area.

5 0

3 years ago

10 • 1/10 =1 a) This is an example of the additive inverse property

saul85 [17]

Answer:

C) Multiplicative Inverse Property

Step-by-step explanation:

Because 1/10 is the inverse of 10.

For example, 15*(1/15)=1.

5 0

3 years ago