Question

Can someone help me solve (x+18)^(1/2)+2=x

Answer 1

Lets solve your equation step by step:
(x+18)^1/2+2=x
step 1:Add -2 to both sides:
(x+18)^1/2+2-2=x+-2
(x+18^)1/2=x-2
step 2:solve exponent
(x+18)^1/2=x-2
((x+18)^1/2)^2=(x-2)^2
x+18=x^2-4x+4
x+18-(x^2-4x+4)=x^2-4x+4-(x^2-4x+4) (subtract x^2-4x+4 from both sides)
-x^2+5x+14=0
(-x-2)(x-7)=0(factor left side of equation)
-x-2=0 or x-7=0 (set factors equal to zero)
x=-2 or x=7

check answers:(plug them in to make sure they work )
x=-2(doesn't work in original equation)
x=7(works in original equation)