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Brrunno [24]
3 years ago
8

PLEASE ANSWERRRRR! EASY!!!!!!!!!!!!!

Mathematics
1 answer:
juin [17]3 years ago
3 0
What even is the 4 I guess
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grandymaker [24]

5 15/32 is the answer

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If -1 is one of the zeroes of py 3x^3-5x^2-11x-3 find other zeroes
katrin2010 [14]

Given:

The function is:

y=3x^3-5x^2-11x-3

It is given that -1 is a zero of the given function.

To find:

The other zeroes of the given function.

Solution:

If c is a zero of a polynomial P(x), then (x-c) is a factor of the polynomial.

It is given that -1 is a zero of the given function. So, (x+1) is a factor of the given function.

We have,

y=3x^3-5x^2-11x-3

Split the middle terms in such a way so that we get (x+1) as a factor.

y=3x^3+3x^2-8x^2-8x-3x-3

y=3x^2(x+1)-8x(x+1)-3(x+1)

y=(x+1)(3x^2-8x-3)

Again splitting the middle term, we get

y=(x+1)(3x^2-9x+x-3)

y=(x+1)(3x(x-3)+1(x-3))

y=(x+1)(3x+1)(x-3)

For zeroes, y=0.

(x+1)(3x+1)(x-3)=0

(x+1)=0 and 3x+1=0 and x-3=0

x=-1 and x=-\dfrac{1}{3} and x=3

Therefore, the other two zeroes of the given function are -\dfrac{1}{3} and 3.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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91011121314671234567891p

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