Answer:
<u>Given</u>
- tanθ = 3.454
- θ is in the III quadrant
We know in the III quadrant both sine and cosine are negative.
<u>Use the following identities to get values of sinθ and cos θ</u>
- sinθ = - tanθ/√(1 +tan²θ)
- cosθ = - 1/√(1 +tan²θ)
<u>Substitute the value of tanθ and find sine and cosine:</u>
- sinθ = - 3.454/√(1 + 3.454²) = - 0.961
- cosθ = - 1/√(1 + 3.454²) = - 0.278
ANSWER
EXPLANATION
The given function is
We rewrite this function to obtain,
We now compare this function to
We have
This implies that,
The vertex is (2,-11).
The focus is
Answer:
(13,5)
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
The outlier is the value that is far from the other values in the set
24 is far from the other values
