Based on the fact that the company received 13,300 currency units from a client, the effect on the accounting equation would be increase in assets and increase in equity.
<h3>What is the change in the accounting equation?</h3>
The accounting equation is:
Assets = Equity + Liabilities
The 13,300 currency units would count as cash which is an asset so assets will increase by the amount of $13,300.
The same $13,300 will also count as revenue as the company receives it for services rendered so the revenue will increase. Revenue is an equity account so Equity will increase.
Find out more on the accounting equation at brainly.com/question/24401217
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Answer:
Step-by-step explanation:
I cant see it
<span>Sales went from 48 pairs to 60 pairs:
total change = 60 - 48 = 12
percentage change = 12 / 48 = 0.25 = 0.25*100% = 25%
Answer: 25%</span>
Answer:
Step-by-step explanation:
n=8 f(x) = x² - 4x
convert [0,2] into 8 subintervals
width of each interval is
![\delta x =\frac{2-0}{8}=0.25](https://tex.z-dn.net/?f=%5Cdelta%20x%20%3D%5Cfrac%7B2-0%7D%7B8%7D%3D0.25)
All subintervals are:
[0, 0.25], [0.25, 0.5], [0.5, 0.75], [0.75, 1], [1, 1.25], [1.25, 1.5], [1.5, 1.75] and [1.75, 2]
Let,
be the right end point of each interval i=1,..8
![x_1=0.25, x_2=0.5, x_3=0.75, x_4=1, x_5=1.25, x_6=1.5, x_7=1.75, x_8=2](https://tex.z-dn.net/?f=x_1%3D0.25%2C%20x_2%3D0.5%2C%20x_3%3D0.75%2C%20x_4%3D1%2C%20x_5%3D1.25%2C%20x_6%3D1.5%2C%20x_7%3D1.75%2C%20x_8%3D2)
Reiman sum is
![R_8=\delta x[f(x_1)+f(x_2)+...f(8)]\\\\0.25[f(0.25)+f(0.5)+...+f(2)]\\\\0.25\times[-23.25]\\=-5.8125](https://tex.z-dn.net/?f=R_8%3D%5Cdelta%20x%5Bf%28x_1%29%2Bf%28x_2%29%2B...f%288%29%5D%5C%5C%5C%5C0.25%5Bf%280.25%29%2Bf%280.5%29%2B...%2Bf%282%29%5D%5C%5C%5C%5C0.25%5Ctimes%5B-23.25%5D%5C%5C%3D-5.8125)
Three equations are:
2x+1=6x+3
8x+6=2x+3
8x+4=2x+1
<u>Step-by-step explanation:</u>
Using the digits 0-9, no more than one time each, place a digit in a box to create an equation with a solution x= -1/2 . We need to Create three equations. Formula is below. __ x+ __=__ x+ __ . Let's find out:
2x+1=6x+3
Let's verify this :
⇒ ![2x+1=6x+3](https://tex.z-dn.net/?f=2x%2B1%3D6x%2B3)
⇒ ![4x=-2](https://tex.z-dn.net/?f=4x%3D-2)
⇒ ![x=\frac{-1}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-1%7D%7B2%7D)
8x+6=2x+3
Let's verify this :
⇒ ![8x+6=2x+3](https://tex.z-dn.net/?f=8x%2B6%3D2x%2B3)
⇒ ![6x=-3](https://tex.z-dn.net/?f=6x%3D-3)
⇒ ![x=\frac{-1}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-1%7D%7B2%7D)
8x+4=2x+1
Let's verify this :
⇒ ![8x+4=2x+1](https://tex.z-dn.net/?f=8x%2B4%3D2x%2B1)
⇒ ![6x=-3](https://tex.z-dn.net/?f=6x%3D-3)
⇒ ![x=\frac{-1}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-1%7D%7B2%7D)